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garik1379 [7]
2 years ago
14

Solve the system using substitution x+5y=0 3y+2x=-21

Mathematics
2 answers:
Crazy boy [7]2 years ago
5 0

Answer:

\left \{ {{x = -15} \atop {y=3}} \right.

Step-by-step explanation:

\left \{ {{x + 5y = 0} (1) \atop {3y + 2x = -21}(2)} \right.  \left \{ {{x = -5y} \atop {3y + 2x = -21}} \right.    \left \{ {{x = -5y} \atop {3y + 2*(-5y) = -21}} \right.  \left \{ {{x = -5y} \atop {3y - 10y = -21}} \right. \\ \left \{ {{x = -5y } \atop {-7y = -21}} \right.  \left \{ {{x = -5y} \atop {y= 3 }} \right.  \left \{ {{x = -5 * 3} \atop {y=3}} \right.=> \left \{ {{x=-15} \atop {y=3}} \right.

pochemuha2 years ago
4 0
Ok done. Thank to me :>

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