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garik1379 [7]
3 years ago
14

Solve the system using substitution x+5y=0 3y+2x=-21

Mathematics
2 answers:
Crazy boy [7]3 years ago
5 0

Answer:

\left \{ {{x = -15} \atop {y=3}} \right.

Step-by-step explanation:

\left \{ {{x + 5y = 0} (1) \atop {3y + 2x = -21}(2)} \right.  \left \{ {{x = -5y} \atop {3y + 2x = -21}} \right.    \left \{ {{x = -5y} \atop {3y + 2*(-5y) = -21}} \right.  \left \{ {{x = -5y} \atop {3y - 10y = -21}} \right. \\ \left \{ {{x = -5y } \atop {-7y = -21}} \right.  \left \{ {{x = -5y} \atop {y= 3 }} \right.  \left \{ {{x = -5 * 3} \atop {y=3}} \right.=> \left \{ {{x=-15} \atop {y=3}} \right.

pochemuha3 years ago
4 0
Ok done. Thank to me :>

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tangare [24]

Answer:

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Step-by-step explanation:

In order for the equation not to change, the point (0, 0) must be on the original line and so on the line after dilation. The only equation with (0, 0) as a point on the line is y=4x.

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Alja [10]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
(-7.5) + (-5.3) (-1.9)
Lisa [10]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
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mamaluj [8]

Answer:

x = ± 8

Step-by-step explanation:

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