<span>30v + 50x = 10(3v + 5x) (Answer A)
2k</span>² + 4k = 2k(k + 2) (Answer D)<span>
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Answer:

Now we are supposed to find probabilities that the response time is between 5 and 10 minutes i.e P(5<x<10)
Formula : 
at x = 5


at x = 10


P(-2<z<0.6315)=P(z<0.6315)-P(z<-2)
Refer the z table
P(-2<z<10)=0.7357-0.0228=0.7129
So, the probability that response time is between 5 and 10 minutes is 0.7129
b)the response time is less than 5 minutes
at x = 5


P(x<5)=P(z<-2)=0.0228
So, the probability that the response time is less than 5 minutes is 0.0228
c)the response time is more than 10 minutes
at x = 10


P(x>10) = 1-P(x<10) = 1-P(z<0.63) = 1-0.7357 = 0.2643
So, The probability that the response time is more than 10 minutes is 0.2643
Answer:
3/5
Step-by-step explanation:
turn 3 into 3/1, then multiply the top and bottom to get 3/5.
Answer:
I believe it is c
Step-by-step explanation:
Correct me if I'm wrong but since the two lines look the same length I believe it is c
Answer:
what is the question about the given numbers