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kifflom [539]
3 years ago
5

Five million divided by fivethousand

Mathematics
2 answers:
Phantasy [73]3 years ago
4 0

Answer:

1000 (one thousand)

Step-by-step explanation:

earnstyle [38]3 years ago
3 0

Answer:

5,000,000/5,000 = 1000

Step-by-step explanation:

Take 5 million and divide by 5 thousand like so and you'll come out with 1000. Also, this is an easy one to plug into a calculator.

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Find an equation of the tangent line to the curve 2(x^2+y^2)2=25(x^2−y^2) (a lemniscate) at the point (3,1)
Sholpan [36]
\bf 2[x^2+y^2]^2=25(x^2-y^2)\qquad \qquad 
\begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ 3}}\quad ,&{{ 1}})\quad 
\end{array}\\\\
-----------------------------\\\\
2\left[ x^4+2x^2y^2+y^4 \right]=25(x^2-y^2)\qquad thus
\\\\\\
2\left[ 4x^3+2\left[ 2xy^2+x^22y\frac{dy}{dx} \right]+4y^3\frac{dy}{dx} \right]=25\left[2x-2y\frac{dy}{dx}  \right]
\\\\\\
2\left[ 4x^3+2\left[ 2xy^2+x^22y\frac{dy}{dx} \right]+4y^3\frac{dy}{dx} \right]=50\left[x-y\frac{dy}{dx}  \right]
\\\\\\


\bf \left[ 4x^3+2\left[ 2xy^2+x^22y\frac{dy}{dx} \right]+4y^3\frac{dy}{dx} \right]=25\left[x-y\frac{dy}{dx}  \right]
\\\\\\
4x^3+4xy^2+4x^2y\frac{dy}{dx}+4y^3\frac{dy}{dx}+25y\frac{dy}{dx}=25x
\\\\\\
\cfrac{dy}{dx}[4x^2y+4y^3+25y]=25x-4x^3+4xy^2
\\\\\\
\cfrac{dy}{dx}=\cfrac{25x-4x^3+4xy^2}{4x^2y+4y^3+25y}\impliedby m=slope

notice... a derivative is just the function for the slope

now, you're given the point 3,1, namely x = 3 and y = 1

to find the "m" or slope, use that derivative, namely f'(3,1)=\cfrac{25x-4x^3+4xy^2}{4x^2y+4y^3+25y}

that'd give you a value for the slope

to get the tangent line at that point, simply plug in the provided values
in the point-slope form

\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad
\begin{cases}
x_1=3\\
y_1=1\\
m=slope
\end{cases}\\ \qquad \uparrow\\
\textit{point-slope form}

and then you solve it for "y", I gather you don't have to, but that'd be the equation of the tangent line at 3,1

6 0
3 years ago
9. 1/3(x+6) =8
babunello [35]
9.       ¹/₃(x + 6) = 8
    ¹/₃(x) + ¹/₃(6) = 8
           ¹/₃x + 2 = 8
           <u>       - 2  - 2</u>
            3 · ¹/₃x = 6 · 3
                     x = 18

15.       ¹/₅(x + 10) = 6
      ¹/₅(x) + ¹/₅(10) = 6
                ¹/₅x + 2 = 6
                <u>       - 2  - 2</u>
                 5 · ¹/₅x = 4 · 5
                         x = 20

20.       ¹/₈(24x + 32) = 10
      ¹/₈(24x) + ¹/₈(32) = 10
                     3x + 4 = 10
                     <u>      - 4   - 4</u>
                           <u>3x</u> = <u>6</u>
                            3     3
                             x = 2

32.        5 - ¹/₂(x - 6) = 4
      5 - ¹/₂(x) - ¹/₂(-6) = 4
              5 - ¹/₂x + 3 = 4
              5 + 3 - ¹/₂x = 4
                    8 - ¹/₂x = 4
                 <u>- 8            - 8</u>
                -2 · (-¹/₂x) = -4 · (-2)
                             x = 8

33.      ²/₃(3x - 6) = 3
     ²/₃(3x) - ²/₃(6) = 3
                2x - 4 = 3
                <u>    + 4 + 4</u>
                     <u>2x</u> = <u>7</u>
                      2     2
                       x = 3¹/₂
8 0
3 years ago
Read 2 more answers
4x/x-5 - 3/x-6 simplify
blagie [28]

Answer

-3

Step-by-step explanation:

x=4

4-5=-1

x=3

3-6=-2

-1+-2=-3

7 0
2 years ago
Read 2 more answers
I need help with all please!!
Olenka [21]

Answer:

1. D

2.C

3. A

4.B

5.C

6. C? or D(i think c cause it's 3 places but it can be d because the 0 is just a placeholder)

7.C

8.C

Step-by-step explanation:

3 0
3 years ago
1. You are given the 3rd and 5th term of an arithmetic sequence. Describe in words how to determine the general term.
kozerog [31]

Step-by-step explanation:

1. In an arithmetic sequence, the general term can be written as

xₙ = y + d(a-1), where xₐ represents the ath term, y is the first value, and d is the common difference.

Given the third term and the fifth term, and knowing that the difference between each term is d, we can say that the 4th term is x₃+d and the fifth term is the fourth term plus d, or (x₃+d)+d =

x₃+2d. =x₅ Given x₃ and x₅, we can subtract x₃ from both sides to get

x₅-x₃ = 2d

divide by 2 to isolate d

(x₅-x₃)/2 = d

This lets us solve for d. Given d, we can say that

x₃ = y+d(2)

subtract 2*d from both sides to isolate the y

x₃ -2*d = y

Therefore, because we know x₃ and d at this point, we can solve for y, letting us plug y and d into our original equation of

xₙ = y + d(a-1)

2.

Given the third and fifth term, with a common ratio of r, we can say that the fourth term is x₃ * r. Then, the fifth term is

x₃* r * r

= x₃*r² = x₅

divide both sides by x₃ to isolate the r²

x₅/x₃ = r²

square root both sides

√(x₅/x₃) = ±r

One thing that is important to note is that we don't know whether r is positive or negative. For example, if x₃ = 4 and x₅ = 16, regardless of whether r is equal to 2 or -2, 4*r² = 16. I will be assuming that r is positive for this question.

Given the common ratio, we can find x₆ as x₅ * r, x₇ as x₅*r², and all the way up to x₁₀ = x₅*r⁵. We don't know the general term, but can still find the tenth term of the sequence

8 0
3 years ago
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