Answer: ong
Step-by-step explanation: im straight
![\left[\begin{array}{ccc}22&18\end{array}\right]\times\left[\begin{array}{cccc}5&18&32&40\\25&40&38&12\end{array}\right]\\\\=\left[\begin{array}{cccc}22\cdot5+18\cdot25&22\cdot18+18\cdot40&22\cdot32+18\cdot38&22\cdot40+18\cdot12\end{array}\right]\\\\=\left[\begin{array}{cccc}560&1116&1388&1096\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D22%2618%5Cend%7Barray%7D%5Cright%5D%5Ctimes%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D5%2618%2632%2640%5C%5C25%2640%2638%2612%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D22%5Ccdot5%2B18%5Ccdot25%2622%5Ccdot18%2B18%5Ccdot40%2622%5Ccdot32%2B18%5Ccdot38%2622%5Ccdot40%2B18%5Ccdot12%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D560%261116%261388%261096%5Cend%7Barray%7D%5Cright%5D)
second question:
January: 32 · 22 + 38 · 18 = 704 + 684 = 1388
December: 18 · 22 + 40 · 18 = 396 + 720 = 1116
1388 - 1116 = 272
Answer: $272.
Answer:
The solution to the inequality is all real values of n that respect the following condition: 2 < n < 6
Step-by-step explanation:
First, we need to separate the modulus from the rest of equation. So
3-l4-nl>1
-|4-n|>1-3
-|4-n|>-2
Multiplying everything by -1.
|4-n|<2
How to solve:
|x| < a means that -a<x<a
In this question:
|4-n|<2
-2<4-n<2
This means that:
4 - n > -2
-n > -6
Multiplying by -1
n < 6
And
4 - n < 2
-n < -2
Multiplying by 1
n > 2
Intersection:
Between n > 2 and n < 6 is 2 < n < 6
So the solution to the inequality is all real values of n that respect the following condition: 2 < n < 6
The volume of a cone is one-third of the product of the area of the base times the height, i.e.
(1/3)π(r^2)*h = (1/3)π(3cm)^2 *(8cm) = 75.40 cm^3
Now multiply that by the number of cones: 6 * 75.40 cm^3 = 452.40 cm^3.
Then the answer is 452 cm^3
Step-by-step explanation:
-5+4=-1
-3+4=1
0+4=4
4+4=8