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Mademuasel [1]
3 years ago
15

PLEASE HELP I WILL PUT BRAINLIEST!!

Mathematics
1 answer:
Lilit [14]3 years ago
4 0

Answer: 6 inches.

Step-by-step explanation:

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Hi guys how is your day going?
Dafna11 [192]

Answer:

good u?

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Type the correct answer in each box. Use numerals instead of words,
xeze [42]

Answer:

x = -6,3,15,-12; y = 11,5,-3,15

Step-by-step explanation:

Domain is the x value, so plugged in the x values into the equation and got the y values or range.

8 0
3 years ago
Find the area of the shape shown below. I reallly need help and do not put a unbelieable answer.
larisa [96]

Answer:

63/2 or 31.5

Step-by-step explanation:

we can split this shape into 2, a triangle and a rectangle

A triangle = bh/2 = 7*3*1/2 = 21/2

A rectangle = b*h = 3*7 = 21

21/2 + 21 = 63/2

3 0
3 years ago
Find the derivative.
krek1111 [17]

Answer:

\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

  • Expanding/Factoring

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]:                                                                           \displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \frac{\sqrt{x}}{e^x}

<u>Step 2: Differentiate</u>

  1. Derivative Rule [Quotient Rule]:                                                                   \displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}
  2. Basic Power Rule:                                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}
  3. Exponential Differentiation:                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}
  4. Simplify:                                                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}
  5. Rewrite:                                                                                                         \displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}
  6. Factor:                                                                                                           \displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
3 years ago
Please help I am doing this in class right now
MAVERICK [17]

Answer:

I believe the answer is (9, -13.5)

Step-by-step explanation:

you do 6×1.5 and -9×1.5 to enlarge/dialate the quadrilateral

again I believe this is right so sorry if I am wrong

3 0
3 years ago
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