What you don't want is the value of r(t) becoming negative. Surely that would represent water escaping the reservoir.
How big can (t) get before water actually starts escaping the reservoir?
Essentially, to figure this out r(t) would have to be equal to 0.
700 - 40t = 0
40t=700
t=700/40=17.5
So the first answer is 17.5 seconds. After this amount of time has elapsed the reservoir will start to lose water as r(t) would become negative.
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The reservoir had the least amount of water in it before it was being filled. That was when t=0. The volume of water in the reservoir wasn't negatively impacted as not enough water had escaped it during the 17.5 to 30 second period.
Answer:
what's the question here ?
Answer:
1/4
Step-by-step explanation:
printed part = 210
total pages = 280
probability to open printed page 210/280 =3/4
probability to not open printed page = 1 - probability to open printed page = 1 - 3/4 = 1/4
Step-by-step explanation:
well, when 6 CD cases are 66 mm high, then 1 CD case is 66/6 = 11 mm high.
a)
therefore, 10 CD cases are 11×10 = 110 mm high.
b)
y = 11x
Answer:
<h2>5n</h2>
Step-by-step explanation:
5, 10 ,15, 20
it is going up in 5
so 5n
