1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sveta_85 [38]
2 years ago
14

Does anyone know what X x X x X is?​

Mathematics
1 answer:
egoroff_w [7]2 years ago
6 0

Answer:

Step-by-step explanation:

X³

You might be interested in
2x+7=27 and 3x+1=28 does 2x+7= 3x+1
Savatey [412]
Hey there!

2x + 7 = 27
2x = 20
x = 10

3x + 1 = 28
3x = 27
x = 9

The values for both of these equations are 9 and 10; therefore, the answers are not equivalent.

I hope this helps!
5 0
3 years ago
Read 2 more answers
Find the volume of the following figure. Round the answer to the nearest hundredth if necessary.
telo118 [61]

Answer:

48 yd^3.

Step-by-step explanation:

Volume of a pyramid = 1/3  * height * area of the base.

The area of the triangular base = 1/2 * height * base = 1/2*6*8

= 24 yd^2.

So the volume of the figure

= 1/3 * 6 * 24

= 2*24

= 48 yd^3.

8 0
2 years ago
Shelby made 5 quarts of juice for a picnic .She said that she made1 1/4 of juice/Explain Shelby's mistake
Svetach [21]
<span>1 gallon= 4 quarts 

She made 5 quarts of juice, that means that she has 1 gallon (4 quarts) and one quart left over!
which can be written as 1 1/4!
</span>
8 0
3 years ago
Read 2 more answers
Suppose two dice are tossed and the numbers on the upper faces are observed. Let S denote the set of all possible pairs that can
Thepotemich [5.8K]

Answer:

▪A = {(1,2) (1,4) (1,6) (2,2) (2,4) (2,6) (3,2) (3,4) (3,6) (4,2) (4,4) (4,6) (5,2) (5,4) (5,6) (6,2) (6,4)(6,6)}

▪C bar = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)}

▪A∩B = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)}

▪A∩B bar = {(1,2) (1,4) (1,6) (3,2) (3,4) (3,6) (5,2) (5,4) (5,6)}

▪A bar∪B = {(1,1) (1,3) (1,5) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,3) (3,5) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,3) (5,5) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)}

▪A bar∩C = {(1,1) (1,3) (1,5) (2,1) (2,3) (2,5) (3,1) (3,3) (3,5) (4,1) (4,3) (4,5) (5,1) (5,3) (5,5) (6,1) (6,3) (6,5)}

Step-by-step explanation:

S = {(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)}

A = {(1,2) (1,4) (1,6) (2,2) (2,4) (2,6) (3,2) (3,4) (3,6) (4,2) (4,4) (4,6) (5,2) (5,4) (5,6) (6,2) (6,4)(6,6)} (second die is even)

B = {(1,1) (1,3) (1,5) (2,2) (2,4) (2,6) (3,1) (3,3) (3,5) (4,2) (4,4) (4,6) (5,1) (5,3) (5,5) (6,2) (6,4) (6,6)} (sum of the two numbers is even)

C = {(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,3) (2,5) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,3) (4,5) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,3) (6,5)} (at least one in the pair is odd i.e one of the pair is odd or both are odd)

A bar = {(1,1) (1,3) (1,5) (2,1) (2,3) (2,5) (3,1) (3,3) (3,5) (4,1) (4,3) (4,5) (5,1) (5,3) (5,5) (6,1) (6,3) (6,5)} (the pairs that are not in A)

B bar = {(1,2) (1,4) (1,6) (2,1) (2,3) (2,5) (3,2) (3,4) (3,6) (4,1) (4,3) (4,5) (5,2) (5,4) (5,6) (6,1) (6,3) (6,5)} (the pairs that are not in B)

C bar = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)} (the pairs that are not in C)

▪A = {(1,2) (1,4) (1,6) (2,2) (2,4) (2,6) (3,2) (3,4) (3,6) (4,2) (4,4) (4,6) (5,2) (5,4) (5,6) (6,2) (6,4)(6,6)}

▪C bar = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)}

▪A∩B = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)} (intersection: the pairs that are common to both A and B)

▪A∩B bar = {(1,2) (1,4) (1,6) (3,2) (3,4) (3,6) (5,2) (5,4) (5,6)} (intersection: the pairs that are common to both A and B bar)

▪A bar∪B = {(1,1) (1,3) (1,5) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,3) (3,5) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,3) (5,5) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)} (union: all the pairs in A bar and B )

▪A bar∩C = {(1,1) (1,3) (1,5) (2,1) (2,3) (2,5) (3,1) (3,3) (3,5) (4,1) (4,3) (4,5) (5,1) (5,3) (5,5) (6,1) (6,3) (6,5)} (intersection: the pairs that are common to both A bar and C)

6 0
3 years ago
The operating costs for each machine for one day have an unknown distribution with mean 1610 and standard deviation 136 dollars.
BabaBlast [244]

Answer:

20.27

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

Using the Central Limit Theorem for Means, what is the standard deviation for the sample mean distribution?

This is s when \sigma = 136, n = 45. So

s = \frac{136}{\sqrt{45}} = 20.27

So the correct answer is:

20.27

3 0
3 years ago
Other questions:
  • How do I slice this problem??
    5·1 answer
  • In Nathan’s baseball card collection, 58% of the cards are players form the national league. He has 702 baseball cards. About ho
    12·2 answers
  • What is the height of the shape formed by the sectors shown below?
    14·2 answers
  • Karen wants to get an average of 92% at the end of the semester in her class. She has 1 test left to take before the semester is
    14·1 answer
  • If a and b are the zeros of the quadratic polynomial 4x2+4x+1, find the value of a/b+b/a?
    12·1 answer
  • What is the volume of this figure in cubic inches? <br> a. 32<br> b. 256<br> c. 416 <br> d. 7.680
    6·1 answer
  • Carter, Michelle, and Jen work at a coffee shop. All three of them worked 6 hours on Monday, Michelle and Jen worked 7 hours on
    5·1 answer
  • 1. find measure of A.
    8·1 answer
  • What is Q(1.5) if ()=cos() and Q(x) is centered at /2? Round your answer to 4 decimals, for example, 0.1234.
    8·1 answer
  • 14. If the domain of f(x)= x2 +1 is limited to {0,1,2,3), what is the maximum value of the range?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!