The path of the ball is an illustration of absolute equation.
The equation of the path is: 
The given parameters are:
--- the vertex (i.e. the point where the ball hits the wall)
An absolute function is represented as:
Substitute
Substitute for x and y
Remove absolute bracket
Collect like terms
Solve for a
Simplify
Substitute in
Hence, the equation of the path is:
See attachment for graph that models the path
Read more about absolute equations at:
brainly.com/question/2166748
Isolate the variable by dividing each side by factors that don't contain the variable.
a=- \frac{ x^{2}- \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2} ,- \frac{ x^{2}+ \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2}
Solve for b by simplifying both sides of the equation then isolating the variable.
b= \frac{12}{x}+ \frac{72}{ x^{2} }-2+2a- \frac{4a}{x}+ \frac{ a^{2} }{x}- \frac{2a^{z} }{ x^{2} }
Hopefully i helped ^.^ Mark brainly if possible. Lol once again i saw the same question so why not answer it again!
Answer:
gradient is equal to 0.7
Step-by-step explanation:
line passes on (-2,0) and (0,1.4)
gradient =(y2-y1)/(x2-x1)
=(1.4-0)/-(0--2)
=1.4/2
=1.4/2×10/10
=14/20
=7/10
=0.7
It would be y=-6x+1 in slope intercept form
