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Triss [41]
2 years ago
11

A little monkey had some peaches. On the first day he decided to keep ½ of his peaches. He gave the rest away. Then he ate one.

On the second day he decided to keep ½ of his peaches. He gave the rest away then he ate one. On the third day he decided to keep ½ of his peaches. He gave the rest away. Then he ate one. On the fourth day, he found he had only one peach left. How many did he have at the beginning?
Mathematics
1 answer:
Hunter-Best [27]2 years ago
8 0

Answer:

22

Step-by-step explanation:

Working backwards

1+1 then x2 is 4

4+1 then x2 is 10

10+1 then x2 is 22

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Read 2 more answers
Please help me please!<br> Also, please show your work image shown below in attachment
WINSTONCH [101]

Answer:

see below

Step-by-step explanation:

some of your answers that you currently have are wrong, I'll note those mistakes below

- when factoring (ie 5x+15) only factor out things that can divide both numbers into a whole number ratio

5x+15 = 5(x+3), not (x+3)(x+5)

ie  \frac{10x^2+20x}{x+2}

we see that 10x can divide the numerator in a whole number ratio

10x^2+20x = 10x(x+2), not (x+2)(x+10)

second mistake: the first binomial expansion is incorrect.

you have the expansion formula right, but you added terms wrong, go look at it again

3. x^2+3x+2/ x^2+5x+6

(x+1)(x+2)/(x+3)(x+2)

(x+1)/(x+3)

4. (x^2+6x+8)/(x^2-16)

(x+4)(x+2)/(x+4)(x-4)

(x+2)/(x-4)

5. we can't simplify that any more, x and y are different variables so therefore we cannot cross out stuff on numerator and denominator

6. (x^4y^6)^2

(x^4y^6)(x^4y^6) = x^8y^{12}

remember that (x^a)(x^b) = x^(a+b)

or remember that (x^a)^b = x^ab

6 0
3 years ago
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