<span>If we were to put this in terms of a venn diagram, we would have 360 owning only brand X, 500 owning only brand Y, and 80 in between, owning both. Therefore, 80 out of the 580 owners of brand Y may have X as well, which we put into fraction form 80/580, and reduce to 4/29.

The answer is the fourth choice 4/29.

I hope my answer has come to your help. God bless and have a nice day ahead!

</span>

7 0

3 years ago

F(x)=2x^(2)-5x-20 find f(-9)

Fed [463]

Answer:

Step-by-step explanation:

$f(x) = 2 {x}^{2} - 5x - 20$

To find f(-9) , substitute the value of x that's - 9 into f (x). That is for every x in f(x) replace it with - 9

We have

$f( - 9) = 2 ({ - 9})^{2} - 5( - 9) - 20 \\ = 2(81) + 45 - 20 \\ = 162 + 25 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = 187 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

We have the final answer as

Hope this helps you

7 0

3 years ago

Read 2 more answers

Quadrilateral KMPT is dilated by a scale factor of 3/4 to create K'M'P'T'. The perimeter of quadrilateral KMPT is x units. What

777dan777 [17]

Answer:

B) $\frac{3}{4}$ x units

Step-by-step explanation:

Let quadrilateral KMPT be a rectangle with dimensions 12 units by 8 units. Then its perimeter would be equal to:

Perimeter of a rectangle = 2 (l + b)

where: l is the length = 12 units and b is the breadth = 8 units. So that:

Perimeter of KMPT = 2 (12 + 8)

= 40 units

Dilating KMPT by a scale factor of $\frac{3}{4}$ would create K'M'P'T' of dimensions; $\frac{3}{4}$ × 12 units by $\frac{3}{4}$ × 8 units. Thus, the dimensions of K'M'P'T' would be 9 units by 6 units.

Perimeter of K'M'P'T' = 2 (l + b)

= 2(9 + 6)

= 30 units

Comparing the perimeters of KMPT and K'M'P'T', the perimeter of K'M'P'T' would be $\frac{3}{4}$ × perimeter of KMPT.

Therefore, if the perimeter of KMPT is x units, then;

perimeter of K'M'P'T' = $\frac{3}{4}$ * x units

= $\frac{3}{4}$ x units

6 0

3 years ago