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iris [78.8K]
3 years ago
8

Factor these expressions into an equivalent form.

Mathematics
2 answers:
Marrrta [24]3 years ago
7 0
(c+8)(c-8)

3(2y+5)(2y-5)

There are no like terms so it's still ab^2-b
damaskus [11]3 years ago
3 0
<h2>Answer:</h2>

a)

c^2-64=(c-8)(c+8)

b)

12y^2-75=3(2y-5)(2y+5)

c)

ab^2-b=b(ab-1)

<h2>Step-by-step explanation:</h2>

a)

c^2-64

This expression could also be given by:

c^2-8^2

Now, we know that:

a^2-b^2=(a-b)(a+b)

Hence, we have:

c^2-64=(c-8)(c+8)

b)

12y^2-75

12y^2-75=3(4y^2-25)

which is further given by:

12y^2-75=3((2y)^2-5^2)\\\\12y^2-75=3(2y-5)(2y+5)

c)

ab^2-b

we take out common b from both the terms to get:

ab^2-b=b(ab-1)

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