Question

Factor these expressions into an equivalent form.

Answer 1

(c+8)(c-8)

3(2y+5)(2y-5)

There are no like terms so it's still ab^2-b

Answer 2

Answer:

a)

$c^2-64=(c-8)(c+8)$

b)

$12y^2-75=3(2y-5)(2y+5)$

c)

$ab^2-b=b(ab-1)$

Step-by-step explanation:

a)

$c^2-64$

This expression could also be given by:

$c^2-8^2$

Now, we know that:

$a^2-b^2=(a-b)(a+b)$

Hence, we have:

$c^2-64=(c-8)(c+8)$

b)

$12y^2-75$

$12y^2-75=3(4y^2-25)$

which is further given by:

$12y^2-75=3((2y)^2-5^2)\\\\12y^2-75=3(2y-5)(2y+5)$

c)

$ab^2-b$

we take out common b from both the terms to get:

$ab^2-b=b(ab-1)$