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2 years ago

I need help with this problem

Mathematics

2 answers:

Neporo4naja [7]2 years ago

8 0

Well if you look at the table, it shows how many holes and scores there are, if you look under 9 ...... it will equal -1

Sergio [31]2 years ago

5 0

-1+0+2+1-2-1-1+2-1

-1 + 3 - 3 + 1 - 1

2 - 2 - 1

-1

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I can’t explain look at picture

const2013 [10]

Answer:

x = 12.48

y = 13.22

Step-by-step explanation

Im not sure if its correct

10^2 + b^2 = 16^2

100 + b^2 = 256

b^2 = √156

b = 12.48

b= 12 ( If needed to round to the nearest whole number)

a^2 + 15^2 = 20^2

a^2 + 225 = 400

a^2 = √175

a = 13.22

a = 13 ( If needed to round to nearest whole number)

3 0

2 years ago

The Eiffel Tower is about 301 meters tall. Cooper is making a scale model of it using the scale 750 meters : 1 meter.

vaieri [72.5K]

Hi im doing this test right now and what is the answer lol

7 0

3 years ago

Suppose a certain population satisfies the logistic equation given by dP

Ksenya-84 [330]

Answer:

The population when t = 3 is 10.

Step-by-step explanation:

Suppose a certain population satisfies the logistic equation given by

$\frac{dP}{dt}=10P-P^2$

with P(0)=1. We need to find the population when t=3.

Using variable separable method we get

$\frac{dP}{10P-P^2}=dt$

Integrate both sides.

$\int \frac{dP}{10P-P^2}=\int dt$ .... (1)

Using partial fraction

$\frac{1}{P(10-P)}=\frac{A}{P}+\frac{B}{(10-P)}$

$A=\frac{1}{10},B=\frac{1}{10}$

Using these values the equation (1) can be written as

$\int (\frac{1}{10P}+\frac{1}{10(10-P)})dP=\int dt$

$\int \frac{dP}{10P}+\int \frac{dP}{10(10-P)}=\int dt$

On simplification we get

$\frac{1}{10}\ln P-\frac{1}{10}\ln (10-P)=t+C$

$\frac{1}{10}(\ln \frac{P}{10-P})=t+C$

We have P(0)=1

Substitute t=0 and P=1 in above equation.

$\frac{1}{10}(\ln \frac{1}{10-1})=0+C$

$\frac{1}{10}(\ln \frac{1}{9})=C$

The required equation is

$\frac{1}{10}(\ln \frac{P}{10-P})=t+\frac{1}{10}(\ln \frac{1}{9})$

Multiply both sides by 10.

$\ln \frac{P}{10-P}=10t+\ln \frac{1}{9}$

$e^{\ln \frac{P}{10-P}}=e^{10t+\ln \frac{1}{9}}$

$\frac{P}{10-P}=\frac{1}{9}e^{10t}$

Reciprocal it

$\dfrac{10-P}{P}=9e^{-10t}$

$P(t)=\dfrac{10}{1+9e^{-10t}}$

The population when t = 3 is

$P(3)=\dfrac{10}{1+9e^{-10\cdot 3}}$

Using calculator,

$P=9.999\approx 10$

Therefore, the population when t = 3 is 10.

8 0

2 years ago

If a certain object has a density of 223 g/cm3 and a mass of 26 grams

maks197457 [2]

Answer:

0.11659...cm3

Step-by-step explanation:

To find volume you would have to plug it in the formula Volume= Mass / density so if we plug it in it will be, X(volume): 26(mass)/223(density) you will get 0.11659...cm3

4 0

2 years ago

James is fencing off a triangular region for his cats to play in. From the first fence post, he walks 13 meters in a straight li

GenaCL600 [577]

You can use Heron's formula to do this

Area of triangle = sqrt[ s(s-a)(s-b)(s-c) ] where s = half the perimeter of the triangle =
1/2 * 13+5+9 = 13.5
so required area = sqrt [ (13.5)(13.5-13)(13.5-5)(13.5-9)]
= 16.1 square meters

4 0

3 years ago