Answe
The University of Baltimore
ACCT: Accounting. ACCT 201 INTRODUCTION TO FINANCIAL ACCOUNTING (3) ...
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sat
no
Explanation:
Based on the information given regarding the sampling, the correct option is E. No, because p = 0.53 was one of the most common values in the sampling distribution.
<h3>How to solve the sample.</h3>
From the complete information, it can be deduced that on the dotplot, the center of the sampling distribution is around 0.53. This means that if we construct a confidence interval, there is a high probability that it will have a value of 0.53.
Also, for less than 53% to be true, then most of the dots should have been less than 0.53. In this case, it is centered around 0.53 and so this illustrates that a lot of values are equal to and above 0.53.
Learn more about sampling on:
brainly.com/question/17831271
Answer:
3 groups of 5
Explanation:
if x is the number of groups of four, and y is the number of groups of five, then 4x +5y =39 (four students per group of four times the # of groups of four, and 5 students per group times the # of groups of five, which should equal the total amount of students, 39). also, x+y=9. (number of each type of group = 9 groups total).
then, use these two equations and solve for y, by "canceling out" x. there are many ways to do this, but i'm going to use subtraction.
4x-5y=39
x+y=9
you want to change the equation
x+y=9
into
4x+4y=36
by multiplying the whole equation by four. because in order to cancel out the x, you need it to equal zero. in the first equation, its 4x.
so its now
4x-5y =39 MINUS
4x+4y=36
___________
y=3
you can check your work because the remaining 6 groups of four (24 total students) plus the 3 groups of five (15 total students) adds up to equal 36
Answer:
<h2>Their Strength</h2>
Explanation:
<h2>Where's the choices my answer is their Strength I think</h2>
