Ask question

Ask question

All categories

2 years ago

15

Which binomials are factors of x^2−3x−54?

1 answer:

denis23 [38]2 years ago

5 0

Correct Options:- A) x-9 and E) x+6

Step by Step Solution:

You might be interested in

4/7×3/4 in simplest form

vlabodo [156]

4/7 × 3/4
(4 and 4 are cancelled )
7×3
the answer is 21

3 0

3 years ago

Help me out pleaseee

spayn [35]

Answer:

Option B is the correct choice.

Step-by-step explanation:

The graph is attached below.

We have to find the $x$ intercept meaning the value of the point on $x-axis$ when $y=0$

So we will put the value of zero $(0)$ instead of $y$ in our given equation.

So here we have solved it algebraically.

$y=\frac{3}{4}x-3$

Putting $y=0$

$0=\frac{3}{4}x-3$

$0=\frac{3x-12}{4}$

Multiplying $4$ both sides.

$0=3x-12$

Adding $12$ both sides.

$12=3x$

Dividing with $3$ both sides.

$x=\frac{12}{3}=4$

So the x-intercept of the given equation is $4$ which can be written as $(4,0)$ in terms of coordinates.

Option B $(4,0)$ is the correct choice.

8 0

2 years ago

What numbers multiplied by themselves give the following: 4 36 64 121

Dmitry [639]

Answer:

2, 6, 8, 11

Step-by-step explanation:

A number multiplied by itself gives a perfect square.

4 = 2²

36 = 6²

64 = 8²

121 = 11²

4 0

3 years ago

Craig went out to a restaurant for dinner. He tipped 16% of his bill, which brought the sum of the dinner bill plus the tip to $

alexira [117]

$22.50

You can get this by dividing the new total by 116%, which is how much of the bill was paid.

4 0

3 years ago

What are the solutions to the following system?

bija089 [108]

The solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Solution:

Given equation:

$-2 x^{2}+y=-5$

Add $2 x^{2}$ on both sides.

$-2 x^{2}+y+2 x^{2}=-5+2 x^{2}$

$y=-5+2 x^{2}$ -------- (1)

$y=-3 x^{2}+5$ (given) -------- (2)

Equate (1) and (2).

$-5+2 x^{2}=-3 x^{2}+5$

Add $3 x^{2}$ on both sides.

$-5+2 x^{2}+3 x^{2}=-3 x^{2}+5 +3 x^{2}$

$-5+5x^{2}=5$

Add 5 on both sides.

$-5+5x^{2}+5=5+5$

$5x^{2}=10$

Divide by 5 on both sides, we get

$x^{2}=2$

Taking square root on both sides, we get

$x=\sqrt{2}, x=-\sqrt{2}$

Substitute $x=\sqrt{2}$ in (1).

$y=-5+2(\sqrt{2})^2$

$y=-5+4$

$y=-1$

Substitute $x=-\sqrt{2}$ in (1).

$y=-5+2(-\sqrt{2})^2$

$y=-5+4$

$y=-1$

Therefore the solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Option C is the correct answer.

6 0

3 years ago