Find the seventh term of the expansion of (3x+7y)^11
2 answers:
13,207,982,634 x⁵y⁶
Step-by-step explanation:
We understand that in Binomial Theorem, expounding of polynomial functions, we have a rule that also involves the use of Pascal's Triangle to find the Coefficients that will be used to multiply each variable as the polynomial function is multiplied by itself several times;
(3x + 7y)^11 = ₁₁C₀ (3x)¹¹(7y)⁰ + ₁₁C₁ (3x)¹⁰(7y)¹ + ₁₁C₂ (3x)⁹(7y)² + ₁₁C₃ (3x)⁸(7y)³ + ₁₁C₄ (3x)⁷(7y)⁴ + ₁₁C₅ (3x)⁶(7y)⁵ + ₁₁C₆ (3x)⁵(7y)⁶....
The 7th term in our case is;
₁₁C₆ (3x)⁵(7y)⁶
According to the attached Pascals Triangle, the coefficient for our term should be 462, so;
462 (3x)⁵(7y)⁶
= 462 (243x⁵) (117,649y⁶)
= 13,207,982,634 x⁵y⁶
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