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makvit [3.9K]
2 years ago
12

Find the value of x when y equals -7.2(3x - 7) = 9y​

Mathematics
2 answers:
Morgarella [4.7K]2 years ago
8 0

Answer:

not sure but its x=4

Step-by-step explanation:

Ber [7]2 years ago
3 0

Hey there!


2(3x - 7) = 9y

2(3x - 7) = 9(-7)

2(3x - 7) = -63

2(3x) + 2(-7) = -63

6x - 14 = -63

ADD 14 to BOTH SIDES

6x - 14 + 13 = -63 + 13

SIMPLIFY IT!
6x = -63 + 13

6x = -49

DIVISION 6 to BOTH SIDES

6x/6 = -49/6

SIMPLIFY!
x = -49/6

x = -8 1/6


Therefore, the answer should be:

x = -8 1/6 (or x = -49/6 [EITHER OF THOSE SHOULD BE YOUR RESULT BECAUSE THEY ARE BOTH EQUAL TO EACH OTHER])


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

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X + 2xy- y^2 = 2<br><br> find dy/dx using implicit differentiation
AleksandrR [38]

Answer:

hope that helps

Step-by-step explanation:

3x^2+2xy+y2=2

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8 0
3 years ago
What is the value of x?
pickupchik [31]

The angles are congruent meaning that you can set them equal to each other:

26 = 5x + 11

Now you can solve for x

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8 0
3 years ago
Read 2 more answers
How do you do this question please help me
Varvara68 [4.7K]
Well then you just do 15-6 right?


whats so hard bout this question?

brainliest would help
8 0
3 years ago
Plzz help me im going to most more like this because im not understanding it
lisov135 [29]
Hi there!

In order to solve, you can use substitution. This means that you use one equation and solve for one variable, then use that one equation and plug it into the other equation. Here's how we'd do it:

WORK:
x = 12 - y (since x is already solved for, we'll use that to plug into the other given equation.
2(12 - y) + 3y = 29 (using substitution)
24 - 2y + 3y = 29
24 + y = 29
y = 5
Plug the value of y back into the first equation
x = 12 - 5
x = 7

ANSWER:
A - x = 7, y = 5

It seems as though you're having some trouble with these questions, PLEASE MESSAGE ME!! I'd be more than happy to help you work through as many problems as you need until you get the hang of it (plus, it doesn't cost you any points!)

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
5 0
3 years ago
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