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1 year ago

How tall is the tower?

Mathematics

1 answer:

Karo-lina-s [1.5K]1 year ago

5 0

Answer:

93.6 ft

Step-by-step explanation:

$\bf \cfrac{AB}{BC} = \tan(60)$

$\bf \cfrac{x}{50} = \sqrt{50}$
$\bf x = 50 \sqrt{3}$

Length of tower:-

$\bf x + 7$
$\bf 50 \sqrt{3} + 7$
$\bf 93.6025$
$\bf = 93.6$

Therefore, the tower is 93.6ft tall.

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There were 178 old cars at the junkyard. Then a truck brought in some more cars. Now there are a total of 236 cars in the junkya

crimeas [40]

Answer:

The correct answer is 58 cars.

Step-by-step explanation:

Cars in the junkyard before the truck arrived with some = 178

Cars after the truck brought into the junkyard some more= 236

Cars brought in by the truck = 236 - 178

Cars brought into the junkyard by the truck = 58

The number of cars brought by the truck is 58 cars.

5 0

3 years ago

businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message

KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let X = number of text messages receive or send in an hour.

The random variable X follows a Poisson distribution with parameter λ.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: $\lambda=\frac{62.7}{24}= 2.6125$ .

The probability of a random variable can be computed using the formula:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...$

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

$P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180$

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

$=1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667$

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

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3 years ago

HELP ME WITH 16 & 17

damaskus [11]

__Data__

The equilateral's lengths are all the same

Also if AB = AD = BD = CD that would mean all those sides have the exact same length

Answers and Explanations

15A. BCD has 2 acute angles and one obtuse angle, so this is an Obtuse Triangle

15B. If beforementioned = 5 cm

Then the perimeter is 5cm x 3 = 15cm

15C. ABC is a Right Triangle

16. abcdef. Measure the angles using a protractor

17. The shortest side of ABC is AB which is 5cm, the longest is AC which is 10cm

Shortest side: Longest side

5cm:10cm

1:2 is the ratio

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2 years ago

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What do you mean about that?

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3 years ago

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Answer:

Step-by-step explanation:

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2 years ago