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bearhunter [10]
2 years ago
5

Answer ASAP!

Mathematics
1 answer:
Alex Ar [27]2 years ago
6 0
I multiplied the dimensions and divided it by 75, got 8.75 but you need to round in this situation, so 9
hope this helps :)
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Solve the problem.
marta [7]

Answer:

There will be 90 ways to reach Greenup from Charleston.

Step-by-step explanation:

<em>Option C: 90 is correct.</em>

Let's name all the ways and try to visualize the roads.

C = Charleston

M = Mattoon

T = Toledo

G = Greenup

Task = Charleston to Greenup. How many different ways to reach?

    1            1          

    2           2           1

C   3     M   3   T      2   G

     4           4           3

     5           5

                   6

So, Refer to this above diagram.

If we Start from C then go to 1 and then go to M and then go to 1 and then go to T and then go to 1 and then go G.

If you notice, in this single possibility we have 3 ways: C to 1 to M, M to 1 to T, T to 1 to G.

It means we will have: 5 x 6 x 3 = 90 number of ways to reach greenup from Charleston.

8 0
3 years ago
To which place value is the number rounded? 8.293 to 8.29?
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It is rounded to the hundredths. 
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According to a certain website, wine critics generally use a wine-scoring scale to communicate their opinions on the relative qu
const2013 [10]

Answer:

\bar x = 82

\sigma =  9.64

Step-by-step explanation:

Given

n = 12

87\ 91\ 86\ 82\ 72\ 91\ 60\ 77\ 80\ 79\ 83\ 96

Solving (a); Point estimate of mean

To do this, we simply calculate the sample mean

\bar x = \frac{\sum x}{n}

\bar x = \frac{87+ 91+ 86+ 82+72+91+60+77+80+79+83+96}{12}

\bar x = \frac{984}{12}

\bar x = 82

Solving (b); Point estimate of standard deviation

To do this, we simply calculate the sample standard deviation

\sigma = \sqrt{\frac{\sum(x-\bar x)^2}{n - 1}

\sigma = \sqrt\frac{(87-82)^2+ (91-82)^2+ ....+ (79-82)^2+ (83-82)^2+ (96-82)^2}{12-1}

\sigma = \sqrt\frac{1022}{11}

\sigma = \sqrt{92.91}

\sigma =  9.64

<em>Note that: The sample mean and the sample standard deviation are the best point estimators for the mean and the standard deviation, respectively.</em>

<em>Hence, the need to solve for sample mean and sample standard deviation</em>

3 0
3 years ago
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