Oxidation numbers is the right answer
Enthalpy change during the dissolution process = m c ΔT,
here, m = total mass = 475 + 125 = 600 g
c = <span>specific heat of water = 4.18 J/g °C
</span>ΔT = 7.8 - 24 = -16.2 oc (negative sign indicates that temp. has decreases)
<span>
Therefore, </span>Enthalpy change during the dissolution = 600 x 4.18 X (-16.2)
= -40630 kJ
(Negative sign indicates that process is endothermic in nature i.e. heat is taken by the system)
Thus, <span>enthalpy of dissolving of the ammonium nitrate is -40630 J/g</span>
1(False)
2(True)
3(False)
4(True)
5(True)
6(True)
The -1 charge means that there is one more electron than protons, so there are 85 protons
Answer : The equilibrium constant for this reaction is,
Explanation :
The given main chemical reaction is:
;
The intermediate reactions are:
(1) ;
(2) ;
We are reversing reaction 1 and multiplying reaction 2 by 2 and then adding both reaction, we get:
(1) ;
(2) ;
Thus, the equilibrium constant for this reaction will be:
Thus, the equilibrium constant for this reaction is,