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2 years ago

What is the Volume! ~

Mathematics

2 answers:

Lynna [10]2 years ago

7 0

Answer: Volume = 108 cm ³

Explanation:

For a square pyramid, the volume can be calculated as follows:

Volume = * area of base * height

Volume = * side² * height

We have:

side length = 6 cm

height = 9 cm

Therefore:

Volume = * 36 * 9 = 108 cm ³

Hope this helps :)

Mrrafil [7]2 years ago

6 0

Answer:

Step-by-step explanation:

Volume of a Square Pyramid :

V = 1/3 x Base Area x Height

Solving :

V = 1/3 x (6)² x 9
V = 36 x 3
V = <u>108</u> cubic centimeters

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Answer:

Step-by-step explanation:

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3 years ago

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The first one is BC
The second one is AB

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3 years ago

Help I have to turn these in fast I'll give brainliest

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Answer:

<h3><u>Firs</u><u>t</u><u> </u><u>q</u><u>uestion</u></h3>

To find ? we use sine

sin ∅ = opposite / hypotenuse

From the question

The hypotenuse is 50

The opposite is 25

So we have

sin ? = 25 / 50

sin ? = 1/2

? = sin-¹ 1/2

<h3><u>Sec</u><u>ond</u><u> </u><u>q</u><u>uestion</u></h3>

To find ? we use tan

tan ∅ = opposite / adjacent

From the question

the opposite is 8

the adjacent is 33

So we have

tan ? = 8/33

? = tan-¹ 8/33

? = 13.62

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3 years ago

Integrate 1 - x / x(x2 + 1) d x by partial fractions.

solniwko [45]

Answer:

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

Step-by-step explanation:

step 1:- by using partial fractions

$[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }$ ......(1)

solving on both sides

$1-x=A(x^{2} +1)+(Bx+C)x......(2)$

substitute x =0 value in equation (2)

1=A(1)+0

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

<u>-</u>1 = C

<u>step 3:-</u>

substitute A,B,C values in equation (1)

now

$\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 } d x -\int\limits \frac{1}{x^{2}+1 } d x$

by using integration formulas

i) by using $\int\limits \frac{1}{x} d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\$ .....(b)

$\int\limits tan^{-1}x dx =\frac{1}{1+x^{2} } +C$ .....(c)

by using above integration formulas (a,b,and c)

we get answer is

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

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3 years ago

On a number line, a number, b, is located the same distance from 0 as another number, a, but in the opposite direction. The

oksian1 [2.3K]

Answer:

b=-a

Step-by-step explanation:

we know that b is located the same distance from 0 as another number, a, but in the opposite direction.

so the sum of the two numbers equal zero

a+b=0

a=-b or b=-a

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3 years ago