Explanation:
The first step is to figure out what the equation is. When unconventional math symbols are used, and when there are no grouping symbols identifying operands, that can be the most difficult step. Here, we think the equation is supposed to be ...
![\sqrt[3]{x+1}-2=0](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%7D-2%3D0)
It usually works well in radical equations to isolate the radical. Here that would mean adding 2 to both sides of the equation, to undo the subtraction of 2.
![\sqrt[3]{x+1}=2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%7D%3D2)
Now, it is convenient to raise both sides of the equation to the 3rd power.

Finally, we can isolate the variable by undoing the addition of 1. We accomplish that by adding -1 to both sides of the equation.

The equation is solved. The solution is x = 7.
In this problem, you combine the like terms...
4a - 3b + 7a
4a and 7a are like terms so you add them together.
4a + 7a = 11a
So, the answer is: 11a - 3b
X+5 ≤ -17
Or if it’s y instead of x put that.
Hope this helps though
Answer: " 3.4 (3c + 3) " .
_____________________________________
Note: "(3.4) * 3 = 10.2" .
_____________________________________
So; " (3.4)c + 10.2 = 3.4 (3c + 3) " .
_____________________________________
Answer:
Part 1) The engine speed that maximizes torque is 
Part 2)The maximum torque is 
Step-by-step explanation:
<u><em>The correct equation is</em></u>

This is the equation of a vertical parabola open downward (because the leading coefficient is negative)
The vertex represent a maximum
The x-coordinate of the vertex represent the engine speed that maximizes torque
The y-coordinate of the vertex represent the maximum torque
Solve the quadratic equation by graphing
using a graphing tool
The vertex is the point (3.093,74.683)
see the attached figure
therefore
The engine speed that maximizes torque is
---> because is in thousands of revolutions per minute
The maximum torque is
