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Given :-
- Time = 5 hours
- Speed = 120 km/h
To find:
We know:-
- Distance = Speed × Time
- Distance = 5 × 120
- Distance = 600km
Required Answer :-
600 km
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The length of a side is 18.
Here is my work attached:
Answer:
Q(t) = Q_o*e^(-0.000120968*t)
Step-by-step explanation:
Given:
- The ODE of the life of Carbon-14:
Q' = -r*Q
- The initial conditions Q(0) = Q_o
- Carbon isotope reaches its half life in t = 5730 yrs
Find:
The expression for Q(t).
Solution:
- Assuming Q(t) satisfies:
Q' = -r*Q
- Separate variables:
dQ / Q = -r .dt
- Integrate both sides:
Ln(Q) = -r*t + C
- Make the relation for Q:
Q = C*e^(-r*t)
- Using initial conditions given:
Q(0) = Q_o
Q_o = C*e^(-r*0)
C = Q_o
- The relation is:
Q(t) = Q_o*e^(-r*t)
- We are also given that the half life of carbon is t = 5730 years:
Q_o / 2 = Q_o*e^(-5730*r)
-Ln(0.5) = 5730*r
r = -Ln(0.5)/5730
r = 0.000120968
- Hence, our expression for Q(t) would be:
Q(t) = Q_o*e^(-0.000120968*t)
(2) So we know Ethan uses 1/4 cup of milk for his cake. And if he needs to make 3 times the amount of 1 cake, he'll make 3 cakes today. So we multiply the amount of cakes (3) by the amount of milk needed (1/4)
3 * 1/4 = 3/4
Ethan will need 3/4 cups of milk.
(3) We know Isabella need's 2/5 of a gallon of the food to make 1 gallon.
She want's to make 5 gallons, so like the other problem, we multiply the amount of gallons (5) by the amount of food needed (2/5):
5 * 2/5 = 10/5 = 2/1.
Isabella will need 2 gallons of food.
Answer:
It should be -4/7
Step-by-step explanation:
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