-(3x-2)=-4(x+1)-4
-3x+2=-4x-4-4
-3x+4x=-4-4-2
x=-10
Answer:
A) The fraction of sum of money did each child receive is
B) The sum of money did Jeff have $ 3200
Step-by-step explanation:
Given as :
Let The sum of money did Jeff have = $ x
The fraction of money did Jeff's wife get =
of $ x
The remaining money Jeff will have = $ x -
of $ x
I.e The remaining money Jeff will have =
=
A ) The remaining amount of money is divided equally among 4 children
So, The fraction of sum of money did each child receive = 
I.e The fraction of sum of money did each child receive =
B ) If each child will receive $ 600
∴,
= $ 600
Or, 3 x = $ 600 × 16
Or, 3 x = $ 9600
∴ x = 
I.e x = $ 3200
So, The sum of money did Jeff have $ 3200
Hence ,
A) The fraction of sum of money did each child receive is
B) The sum of money did Jeff have $ 3200 Answer
Answer:

Step-by-step explanation:
We see that the two terms share an x, so we can pull that out:

Now notice that we have a difference of squares (
). Given a difference of squares,
, this can always be factored into
. We can use this in this case:
.
So, our final factorized form is:
.
Hope this helps!
Answer:
The answer is B
Step-by-step explanation:
hope that helps
Answer:
(300 + 50x)/(2 + x)
Step-by-step explanation:
Let the cost of teachers' edition books be t
Let the cost of students' edition books be s
So t = 150; s = 50
Then the total cost of 2 teachers' editions and x students' editions is 2t + sx = 2 × 150 + 50x = 300 + 50x.
The total number of books is 2 + x.
So the average cost per book is (300 + 50x)/(2 + x)