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tatyana61 [14]
1 year ago
13

1. Use the circle to estimate the area of the square

Mathematics
1 answer:
ANTONII [103]1 year ago
7 0

Answer:

name a word problem where our number of the day is your solution

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Please help me with this homework
devlian [24]

Answer:

Well rewriting literal equations can help you understand better and you'll have more room to write the answer and figure it out.

Step-by-step explanation:

8 0
3 years ago
Help plz thanks question 1
Varvara68 [4.7K]
-2x^2 + 500x - 350

You need to plug in the equations for C(x) and R(x) into the equation P(x)= R(x) - C(x) and solve.
6 0
2 years ago
Read 2 more answers
Two horses are ready to return to their barn after a long workout session at the track. the horses are at coordinates H(1,10) an
IgorLugansk [536]
The given information are the coordinates of points H, Z and B. So, the first step to do is to plot these points on a Cartesian plane as shown in the attached picture. We can deduce visually that horse Z is closer to the barns than horse H. But, to further justify the answer, we have to provide the magnitude of the distance of horses H and Z to barn B. In this approach, we use the distance formula:

d = √(x₂ - x₁)² + (y₂ - y₁)²

Use the coordinates of the two points to know their linear distances. These are represented by the red and green lines for each of the horses.

Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B  = 19.4165

Since the scale is 1 unit = 100 meters, the actual distance between horse H and barn B is 19.416*100 = 1,941.65 meters


Distance between Z and B = √(⁻3 - 10)² + (⁻9-1)²
Distance between Z and B = √(⁻3 - 10)² + (⁻9-1)²
Distance between Z and B  = 16.4012

Since the scale is 1 unit = 100 meters, the actual distance between horse Z and barn B is 16.4012*100 = 1,640.12 meters

Comparing the distances: 1,941.65 meters > 1,640.12 meters. Therefore, it justifies that horse Z is nearer to the barn.

8 0
2 years ago
What is the x-intercept of the line?
andre [41]

Answer:

(  12, 0 )

Step-by-step explanation:

5 0
2 years ago
Help please
Natali5045456 [20]

Answer:

17 ± sqrt(337)

 -----------------------

     2

Step-by-step explanation:

Let a = shorter leg

b= longer leg = a+7

c = hypotenuse = 2a-5

We can use the Pythagorean theorem

a^2+b^2 = c^2

a^2 + (a+7)^2 = (2a-5)^2

(a+7)^2 = a^2 +7a +7a+49 = a^2 +14a +49

(2a-5)^2 = 2a*2a -10a -10a +25 = 4a^2 -20a +25

Substituting these into the equation

a^2 + (a^2 +14a +49) = (4a^2 -20a +25)

Combine like terms

2a^2 +14a +49 = 4a^2 -20a +25

Subtracting 2a^2 from each side

2a^2 -2a^2 +14a +49 = 4a^2-2a^2 -20a +25

+14a +49 = 2a^2 -20a +25

Subtract 14a from each side

-14a+14a +49 = 2a^2 -20a -14a+25

+49 = 2a^2 -34a +25

Subtract 49 from each side

49-49 = 2a^2 -34a +25-49

0 =  2a^2 -34a -24

Divide each side by 2

0/2 =  2/2a^2 -34/2a -24/2

0 = a^2 -17a -12

Using the quadratic formula

a=1  b= -17  c = -12

17 ±sqrt( (-17)^2 - 4(1)(-12))

----------------------------------

2(1)

 17 ± sqrt(337)

 -----------------------

     2

4 0
2 years ago
Read 2 more answers
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