Equation = a² + b² = c²
a = 80
b = 39
c = Diagonal
a² + b² = c²
80² + 39² = c²
6400 + 1521 = c²
c² = 7921
c = √7921
c = 89
Answer = 89 units
<span>Exactly 33/532, or about 6.2%
This is a conditional probability, So what we're looking for is the probability of 2 gumballs being selected both being red. So let's pick the first gumball.
There is a total of 50+150+100+100 = 400 gumballs in the machine. Of them, 100 of the gumballs are red. So there's a 100/400 = 1/4 probability of the 1st gumball selected being red.
Now there's only 399 gumballs in the machine and the probability of selecting another red one is 99/399 = 33/133.
So the combined probability of both of the 1st 2 gumballs being red is
1/4 * 33/133 = 33/532, or about 0.062030075 = 6.2%</span>
Answer:
Step-by-step explanation:
Use the formula to find the z-score, then go to the table that will give you the probability that the value is less than this z-score.
The probability that the value lies to the left of 1 on a standard bell curve is 84.1345%, or 84%, the third choice down.
Answer: C, D
Step-by-step explanation:
edge2021
Addition and multiplication are commutative property so that mean no.
In this case, you have to do division.
Your answer is 6x = 72
x = 12
Hope this helps :)
