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deff fn [24]
2 years ago
12

Pls help with this thx

Mathematics
1 answer:
Natalija [7]2 years ago
4 0
1. 55
2. N/A - Sorry. I can’t see the numbers properly.
3. 180
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Find the solution of the system of equations.<br>6x + 8y = -8<br>x + 4y = 4<br>( , )​
ladessa [460]

Answer:

the solution is (-4, 2)

Step-by-step explanation:

6x + 8y = -8

x + 4y = 4

... can be solved using elimination by addition and subtraction, among other methods.  Multiply the second equation by -2 to obtain

6x + 8y = -8

-2x - 8y = -8

Combining these results in

4x = -16.  Thus, x = -4.

Substituting -4 for x in x + 4y = 4 results in

-4 + 4y = 4, or 4y = 8, or y = 2

Then the solution is (-4, 2)

8 0
3 years ago
If a tree 41.8 feet tall casts a shadow that is 27 feet long, find the height of a tree casting a shadow that is 18.3 feet long
Neko [114]

Answer:

28.3 feet

Step-by-step explanation:

Given a tree 41.8 feet tall casts a shadow that is 27 feet long

So the Tangent of the angle of the sahdow remains the same for the both trees.

We know that  Tanx=\frac{height of the tree}{length of the shadow}

\frac{height of the tree1}{length of the shadow1} = \frac{height of the tree2}{length of the shadow2}

\frac{41.8}{27} =\frac{x}{18.3}

x=\frac{41.8}{27}\times18.3 =28.3

Therefore the height of the tree is 28.3 feet

6 0
3 years ago
5 divide 3/4 and simply
Aloiza [94]
6 and 2/3 is your answer
5 0
3 years ago
Read 2 more answers
F as a function of x is equal to the square root of quantity 4 x plus 6, g as a function of x is equal to the square root of qua
andriy [413]
<span>f(x)=âš(4x+6) g(x)=âš(4x-6) This is what we are given to work with, originally. Now, for the next part, we are asked to add the functions f(x) and g(x) together - and this is just what you do! You add the functions together, and then combine like terms. (f+g)(x)=âš(4x+6)+âš(4x-6) --> âš(8x) + 6 - 6 :: and the 6's cancel each other, while the root 4x's add... and you have... (f+g)(x)=âš(8x) Thank you very much.</span>
4 0
3 years ago
Some rectangles are not parallelograms
VARVARA [1.3K]

Answer:

I'm not sure what your asking, but, no, all rectangles are parallelograms.

I found this over the internet, and I hope it helps you understand why a rectangle is always a parallelogram, but a parallelogram is not always a rectangle:

It is true that every rectangle is a parallelogram, but it is not true that every parallelogram is not a rectangle. For instance, take a square. It's a parallelogram — it is a quadrilateral with two pairs of parallel faces. But it is also a rectangle — it is a quadrilateral with four right angles.

5 0
3 years ago
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