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Serggg [28]
2 years ago
8

: Find the area of the shaded region for these two questions. Remember this

Mathematics
1 answer:
xxMikexx [17]2 years ago
6 0

Answer:

c) 18 cm²

d) 30 cm²

Step-by-step explanation:

c)

You can do this 2 different ways. Either way, you need to use the bottom side of 8 cm and the two congruent segments. Each of the two congruent segments of the bottom side measures 4 cm.

Method 1) Find the area of the large triangle and subtract from it the area of the small triangle.

area of triangle = bh/2

shaded area = 8 cm × 6 cm / 2 - 4 cm × 3 cm / 2

shaded area = 24 cm² - 6 cm²

shaded area = 18 cm²

Method 2) The shaded region is a trapezoid with parallel bases of lengths 3 cm and 6 cm and height 4 cm. Find the area of the trapezoid.

area of trapezoid = (B + b)h/2

shaded area = (6 cm + 3 cm)(4 cm)/2

shaded area = (9 cm)(4 cm)/2

shaded area = 18 cm²

d)

The area of the shaded region is the area of the white triangle subtracted from the area of the rectangle.

area of rectangle = length × width

area of triangle = bh/2

shaded area = (12 cm)(4 cm) - (9 cm)(4 cm)/2

shaded area = 48 cm² - 18 cm²

shaded area = 30 cm²

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Answer:

The amount of change she received is

$16.1

Step-by-step explanation:

1.what is asked in the problem?

We are to find how much change she received

what are the given facts?

She bought:

notebook which cost 23.75; a set of colored pens which cost 36.20 and a liquid eraser which cost 23.95

She gave the cashier $100

2.what operation to be used to solve the problem ?

Addition and Subtraction operation

3.solve

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= $16.1

The amount of change she received is

$16.1

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3 years ago
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Norma-Jean [14]
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7 0
3 years ago
Find the x and y for numbers 2 and. 3 thank you
OLEGan [10]

Answer:

(0, 4 ) and (2, - 4 )

Step-by-step explanation:

(2)

3x + 4y = 16 → (1)

- 3x + 2y = 8 → (2)

Adding (1) and (2) term by term will eliminate the x- term

0 + 6y = 24

6y = 24 ( divide both sides by 6 )

y = 4

Substitute y = 4 into either of the 2 equations and solve for x

Substituting into (1)

3x + 4(4) = 16

3x + 16 = 16 ( subtract 16 from both sides )

3x = 0 , then

x = 0

solution is (0, 4 )

(3)

2x - 4y = 20 → (1)

5x + 4y = - 6 → (2)

Adding (1) and (2) term by term will eliminate the y- term

7x + 0 = 14

7x = 14 ( divide both sides by 7 )

x = 2

Substitute x = 2 into either of the 2 equations and solve for y

Substituting into (2)

5(2) + 4y = - 6

10 + 4y = - 6 ( subtract 10 from both sides )

4y = - 16 ( divide both sides by 4 )

y = - 4

solution is (2, - 4 )

5 0
3 years ago
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