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wel
3 years ago
12

Will someone help me get this answer? And please explain it.

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
8 0
Do the unit rate and simplify it and. or make an equation
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How do you get to the point (-3.4)? *
kaheart [24]

Answer:

3 down, 4 up

Step-by-step explanation:

-3 is the X line, which starts on 0, if you subtract 3, or add -3, you would have to go down, 3 down. 4 is on the Y line, so you add, go left to add on the Y line, 4 up.

Always start with you X coordinate. Here is a tip to help you (X, Y)

7 0
3 years ago
The Smith Family went out to to dinner.
KatRina [158]
First I will find the tip and then I will add that to the total and THEN I will add my sales tax to find 6% you have to multiply by 0.06.  to find 15% you have to multiply by 0.15

0.06 * 29.85 = 1.79
29.85 + 1.79 = 31.64
0.15 * 31.64 = 4.74
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5 0
3 years ago
Geometry help please
bezimeni [28]

Answer:

x=2

ab=7

bc=5

Step-by-step explanation:

because you do

2x+3 = 4x+3

-3              -3

2x=4x

-2x -2x

x = 2

2x2+3

4+3

=7

4x2-3

8-3

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5 0
3 years ago
Read 2 more answers
What is 5/7*w=40 1/2
sukhopar [10]

Answer:

56 7/10

Step-by-step explanation:

convert 40 1/2 to a fraction 40 1/2 = 81/2

multiply both sides by  7/5

this gets w by itself on the left

81/2 x 7/5 = 567/10 = 56 7/10

7 0
3 years ago
WILL GIVE BRAINLIEST
stira [4]

The air force plane travelled for a total of 6.9 hours.

<u>SOLUTION: </u>

Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph.  A cargo plane left sometime later flying in the same direction at an average speed of 207 mph.  After flying for 5.3 hours the cargo plane caught up with the Air Force plane.  

We have to find the number of hours the Air Force plane flew before the cargo plane caught up.

Now, we know that, \text { distance travelled }=\text { speed } \times \text { time }

For air force plane \rightarrow \text { distance travelled }=159 \mathrm{x} \text { time taken by air force plane }

\text { For cargo plane } \rightarrow \text { distance travelled }=207 \times 5.3 \text { hours }

Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.

So, 159 \times \text { time taken by air force plane }=207 \times 5.3

\Rightarrow =\frac{207 \times 5.3}{159}

\Rightarrow =\frac{1097.1}{159}

Time taken by air force plane = 6.9  hrs

6 0
3 years ago
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