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wel
3 years ago
12

Will someone help me get this answer? And please explain it.

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
8 0
Do the unit rate and simplify it and. or make an equation
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After leaving a warehouse, a trucker drove 28 miles south to make a delivery. The trucker then made three more deliveries, drivi
anastassius [24]
The trucker was 25 miles north from the warehouse.

7 0
3 years ago
Clase, ¿cuánto es 2.000 − 502?
coldgirl [10]

Answer:

1498  or Mil cuatrocientos noventa y ocho (Espanol)

Step-by-step explanation:

2,000 - 502 = 2,000 - 500 - 2.

2,000 - 500 = 1500

1500 - 2 = 1498

6 0
3 years ago
The price of the box of 15 stickers is $6. The price of the box of 25 stickers is $8. All prices are without tax, and the price
REY [17]

Answer:

y=0.2x+3

Step-by-step explanation:

Let

x ----> the number of stickers

y ----> the price of the boxes

we have the points

A(15,6),B(25,8)

<em>Find the slope</em>

m=(8-6)/(25-15)

m=2/10=0.20

<em>Find the equation of the line into point slope form</em>

The equation is equal to

y-y1=m(x-x1)

substitute the value of m and the point A

y-6=0.2(x-15)

y=0.2x-3+6

y=0.2x+3 ----> linear equation that represent the situation

7 0
3 years ago
A runner is running a 10 km race. it takes her 17.5 minutes to reach the 2.5 km mark. at that rate, how long will it take her to
cluponka [151]
First find the unit rate. Do 17.5/2.5 and you get 7. Next just multiply that by 10 and voila. It takes her 70 minutes to run the whole race.
5 0
3 years ago
7-18 use part 1 of the fundamental theorem of calculus to find the derivative of the function.
blondinia [14]

\displaystyle h(x)=\int\limits_{1}^{\sqrt{x}}~\cfrac{z^2}{z^4+1}dz~\hspace{10em}\cfrac{dh}{du}\cdot \stackrel{chain~rule}{\cfrac{du}{dx}\implies \cfrac{dh}{dx}} \\\\[-0.35em] ~\dotfill\\\\ u=\sqrt{x}\implies \cfrac{du}{dx}=\cfrac{1}{2\sqrt{x}} \\\\[-0.35em] ~\dotfill

\cfrac{dh}{dx}\implies \displaystyle \cfrac{d}{du}\left[ \int\limits_{1}^{u}~\cfrac{z^2}{z^4+1}dz \right]\cdot \cfrac{1}{2\sqrt{x}}\implies \left[ \cfrac{u^2}{u^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}} \\\\\\ \stackrel{substituting~back}{\left[ \cfrac{(\sqrt{x})^2}{(\sqrt{x})^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}}}\implies \cfrac{x}{x^2+1}\cdot \cfrac{1}{2\sqrt{x}}\implies \cfrac{\sqrt{x}}{2x^2+2}

7 0
2 years ago
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