19. Given that angle BFC = 58°. Angle BXG = 48° and angle CBF 22 Find () 2BGX (iv) BCG (i) 2BGF (iv) ZBFG (ii) BCF H EE 58 48° D
1 answer:
The unknown angles in the cyclic quadrilateral is as follows:
∠BGX = 74° (sum of angles in a triangle)
∠BGF = 180° (opposite angles of cyclic quadrilateral are supplementary)
∠BCF = 100°(sum of angles in a triangle)
∠BCG = 26°
∠BFG = 22°
<h3>Cyclic Quadrilateral</h3>A cyclic quadrilateral has all its angles equal to 360 degrees. The sum of angles in a cyclic quadrilateral is equals to 360 degrees.
Let's find the missing angles as follows:
∠BGX = 180 - 48 - 58 = 74° (sum of angles in a triangle)
∠BGF = 180 - 100 = 80° (opposite angles of cyclic quadrilateral are supplementary)
∠BCF = 180 - 22 - 58 = 100°(sum of angles in a triangle)
∠BCG = 100 - 74 = 26°
∠BFG ≅ CBF = 22°(alternate angles)
learn more on angles here: brainly.com/question/19430381
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A sailor is 30 m above the water in the crow's nest on a sailboat.
The sailor encounters an orca surface at an angle of depression of 15 degrees.
The crows nest is 20 m horizontally from the bow (front) of the boat.
To Find :
How far in front of the boat is the orca.
Solution :
Let, distance of boat front from the crow's nest is x.
So,
Hence, this is the required solution.
Answer:
a) 0.0167
b) 0
c) 5.948
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 6.16 ounces
Standard Deviation, σ = 0.08 ounces
We are given that the distribution of fill volumes of bags is a bell shaped distribution that is a normal distribution.
Formula:
a) Standard deviation of 23 bags
b) P( fill volume of 23 bags is below 5.95 ounces)
P(x < 5.95)
Calculation the value from standard normal z table, we have,
c) P( fill volume of 23 bags is below 6 ounces) = 0.001
P(x < 6) = 0.001
Calculation the value from standard normal z table, we have,
If the mean will be 5.948 then the probability that the average of 23 bags is below 6.1 ounces is 0.001.