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olasank [31]
3 years ago
8

At which x value will f(x)=3x+3 exceed g(x)=3x+10

Mathematics
2 answers:
Artyom0805 [142]3 years ago
7 0
There are no x value that allows f(x) to exceed g(x). f(x) is parallel to g(x) and it will always be 7 less than g(x).
Anvisha [2.4K]3 years ago
3 0
We write an inequality:

f(x) > g(x)

3^x + 3 > 3x + 10

3^x > 3x + 7

This equation cannot be solved using trivial methods found in high-school classes, so we resort to graphical examination.  3x+7 is a linear function while 3^x is an exponential one (with limit zero as x approaches - \infty).  We see that 3^x = 3x+7 at approximately x=2.4 and x=-2.3.

Indeed, using a computer algebra system such as the ones on modern TI calculators and on many internet sites gives equality at x=2.42, -2.31.  By observing our graph, we see that f(x) > g(x) when x > 2.42 or x < -2.31.
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\boxed{\mathrm{view \ explanation}}

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