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antiseptic1488 [7]
3 years ago
12

Yani buys 4 doxen flyers for $7.25. What is the cost of 12 dozens?

Mathematics
2 answers:
Viefleur [7K]3 years ago
6 0

Answer:

Step-by-step explanation: tienes que hacer 7,25 dividido 4 eso te va a dar 1,8125, ese numero lo multiplicas por 144 que es el resultado de 12 docenas que te va a dar $261. espero sirva

lara31 [8.8K]3 years ago
3 0

Answer: 21.75

Step-by-step explanation: 7.25 times 3

why 3? Because 4 dozens times 3 is 12 dozens

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The simplest way to do this is to set up equivalent fractions. So, you'd do:

\frac{3}{2} = \frac{78}{x} and then solve for x. 

x=52
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Order least from greatest -50 44 -3 1.5
sp2606 [1]

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Step-by-step explanation:

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3 years ago
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notsponge [240]

Answer:

V=90

Step-by-step explanation:

<u>Step 1:  Find the volume of the cone</u>

<u />V = \frac{\pi *r^{2}*h}{3}

<u>Plug in the values</u>

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<u>Simplify and Solve</u>

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3 0
3 years ago
a study is planned to compare the proportion of men who dislike anchovies with the proportion of women who dislike anchovies. th
e-lub [12.9K]

Answer:

d. No because n·(1 - \hat p) = 8.96 is less than 10

Step-by-step explanation:

Question options;

a. Yes because the sample sizes of both groups are greater than 5

b. Yes, because in both cases n·\hat p > 10

c. Yes, because we know that the population is evenly distributed

d. No, because the n·(1 - \hat p) is less than 10

Explanation;

The given data are;

The number of men in the sample of men, n₁ = 41

The proportion of men who dislike anchovies, \hat p_1 = 0.67

The number of women in the sample of women, n₂ = 56

The proportion of men who dislike anchovies, \hat p_2 = 0.84

The assumptions for an analysis of the difference between means using a T-test are;

1) The data should be from a random sample of the population

2) The variables should be approximately normal (n·\hat p ≥ 10, and n·(1 - \hat p) ≥ 10)

3) The scale of the data is a continuous ordinance scale

4) The sample size should be large

5) The sample standard deviations should be approximately equal

From the requirement for normality, we have;

For the sample of men, n₁·\hat p₁  = 41 × 0.67 = 24.47 > 10

n₁·(1 - \hat p₁) = 41 × (1 - 0.67) = 13.53 > 10

For the sample of women, n₂·\hat p₂  = 56 × 0.84 = 47.04 > 10

n₂·(1 - \hat p₂) = 56 × (1 - 0.84) = 8.96 < 10

Therefore, the for n₂·(1 - \hat p₂), the sample does not meet the requirement for normality

The correct option is d. No because n₂·(1 - \hat p₂) = 8.96 is less than 10

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Car gets 22 miles per gallon
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