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crimeas [40]
2 years ago
5

| x- ( - 18) | if x < - 18

Mathematics
1 answer:
aleksandrvk [35]2 years ago
6 0

Answer:

well x-(-18) x+18 but the if part is x<-18 will stay the same

Step-by-step explanation:

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Sherry needs $120 by the end of the month. So far, she has only raised one-fourth of the amount that she needs. How much money h
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The answer is C. Hope this helps
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What is negative 5 and 3/4 as a fraction
Alinara [238K]

Answer:

-23/4

Step-by-step explanation:

-5\frac{3}{5}

-\frac{5x4+3}{4}

-\frac{20+3}{4}

-\frac{23}{4}

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3 years ago
The area of the rectangle as a single expression
Ne4ueva [31]

Answer: A=15x^2+6x-48

Step-by-step explanation:

The area of a rectangle can be calculated with this formula:

A=l*w

Where "l" is the length and "w" is the width.

You can identify from the figure that the length and the width of this rectangle are:

length=3(x+2)\\width=5x-8

Then, you need to substitute this lenght and this width into A=l*w:

A=3(x+2)(5x-8)

Now, apply Distributive property:

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Finally, you need to add the like terms. Then, you get:

A=15x^2+6x-48

5 0
3 years ago
Teddy has two pairs of black shoes and three pairs of brown shoes. He also has one pair of brown pants and three pairs of black
horsena [70]

Answer:

0.20 or 20%

Step-by-step explanation:

Brown shoes = 3

Black shoes = 2

Total shoes = 5

Brown pants = 1

Black shoes = 3

Total pants = 4

Brown socks =4

Black socks = 6

Red socks = 2

Total socks = 12

In order to choose shoes, pants and socks of the same color, Teddy can go either all black or all brown. For all black, there is a 2 in 5 chance he gets the right shoes, 3 in 4 chance for pants and 6 in 12 for socks. For all brown, there is a 3 in 5 chance he gets the right shoes, 1 in 4 chance for pants and 4 in 12 for socks.

P=P(All\ black)+P(All\ brown)\\P=\frac{2}{5}*\frac{3}{4}*\frac{6}{12}+ \frac{3}{5}*\frac{1}{4}*\frac{4}{12}\\P=0.20

The probability that he chooses shoes, pants, and socks of the same color is 0.20 or 20%.

5 0
3 years ago
A class consists of 55% boys and 45% girls. It is observed that 25% of the class are boys and scored an A on the test, and 35% o
Julli [10]

Step-by-step explanation:

Probability of event A on the condition of event B is:

P(A|B) = P(A and B) / P(B)

P(scored an A | girl) = P(scored an A and girl) / P(girl)

P(scored an A | girl) = 0.35 / 0.45

P(scored an A | girl) = 0.778

The probability that a randomly selected girl also scored an A is 77.8%.

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3 years ago
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