Speed=distance/time
suppose the distance of the first day is d, and the time is t
distance of the second day: d+0.17d=1.17d
time of the second day: t+0.2t=1.2t
speed of the second day: 1.17d/1.2t=0.975(d/t)=(1-0.025)(d/t)
so the speed of the second day is 2.5% slower than the first day.
<span>f(x)=-6x-1
</span><span> X Y
0 -1
-1 5
6 -37
5 -31</span>
Answer:
Only 4 is the right answer. The rest all are false.
For question 22, divide each number by 1.41 to see which one produces a quotient larger than 0.9. d is the answer.
For #23, multiple 0.155 million by 86%, the result is 133,300
again, d is the correct answer.
The third one
5/6 is the answer