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Anna71 [15]
2 years ago
5

!!!!!!

Mathematics
1 answer:
juin [17]2 years ago
6 0

Answer:

required Value of x is x=8

Step-by-step explanation:

We are given two points: (5,8) and (x,14) and slope =2 . We need to find value of x.

The formula used to find slope is: Slope=\frac{y_2-y_1}{x_2-x_1}

We are given slope =2 , x₁=5, y₁=8, x₂=x, y₂=14

So, we actually need to find value of x₂. Putting values in formula and find value of x

Slope=\frac{y_2-y_1}{x_2-x_1}\\2=\frac{14-8}{x-5}\\Solving:\\2(x-5)=6\\2x-10=6\\2x=6+10\\2x=16\\x=\frac{16}{2}\\x=8

So, required value of x=8

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[HELP ASAP 50 POINTS] 17, 18, 19, 20
Charra [1.4K]

17) f(x) = 16/(13-x).

In order to find domain, we need to set denominator expression equal to 0 and solve for x.

And that would be excluded value of domain.

13-x =0

Adding x on both sides, we get

13-x +x = x.

13=x.

Therefore, domain is All real numbers except 13.



18).f(x) = (x-4)(x+9)/(x^2-1).

In order to find the vertical asymptote, set denominator equal to 0 and solve for x.

x^2 -1 = 0

x^2 -1^2 = 0.

Factoring out

(x-1)(x+1) =0.

x-1=0 and x+1 =0.

x=1 and x=-1.

Therefore, Vertical asymptote would be

x=1 and x=-1

19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)

We have degrees of numberator and denominator are same.

Therefore, Horizontal asymptote is the fraction of leading coefficents.

That is 7/2.


20) f(x)=(x^2+3x-2)/(x-2).

The degree of numerator is 2 and degree of denominator is 1.

2>1.

Degree of numerator >  degree of denominator .

Therefore, there would no any Horizontal asymptote.

6 0
3 years ago
For what values of a are the following expressions true?/a+5/=-5-a
katovenus [111]

Explanation:

The expression is given below as

|a+5|=-5-a

Concept:

We will apply the bsolute rule below

\begin{gathered} if|u|=a,a>0 \\ then,u=a,u=-a \end{gathered}

By applying the concept, we will have

\begin{gathered} \lvert a+5\rvert=-5-a \\ a+5=-5-a,a+5=5+a \\ a+a=-5-5,a-a=5-5 \\ 2a=-10,0=0 \\ \frac{2a}{2}=\frac{-10}{2},0=0 \\ a=-5,0=0 \end{gathered}

Hence,

The final answer is

a\leq-5

5 0
10 months ago
Find the sum of the first one hundred positive integers. see fig 6.26
nignag [31]
Here's a pattern to consider:
1+100=101
2+99=101
3+98=101
4+97=101
5+96=101
.....
This question relates to the discovery of Gauss, a mathematician. He found out that if you split 100 from 1-50 and 51-100, you could add them from each end to get a sum of 101. As there are 50 sets of addition, then the total is 50×101=5050
So, the sum of the first 100 positive integers is 5050.

Quick note
We can use a formula to find out the sum of an arithmetic series:
s =  \frac{n(n + 1)}{2}
Where s is the sum of the series and n is the number of terms in the series. It works for the above problem.
8 0
3 years ago
James at 26 Apple then he gives away 8 apples how many apples dose James have math
Sergio039 [100]
26 - 8 = 18. 
James has 18 apples.


4 0
3 years ago
Read 2 more answers
)Tessa had $35. She bought a book for $7 and a magazine for $5. Which expression correctly shows the total money Tessa has left?
Sergeu [11.5K]
Total - book $ - magazine $

Which is equal to:

Total + (-book $) + (-magazine $)
$35 + (-$7) + (-$5)


ANSWER: (C) $35 + (-$7) + (-$5)

Hope this helps! :)
4 0
3 years ago
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