The volumes of two similar figures are given. The surface area of the smaller figure is given. find the surface area of the larg
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The plane will end up flying 5.02°.
The plan's speed relative to the ground will be 645.91 km/hr.
Solution:
Use the cosine formula,
Substitute the given values in the formula,
Taking square root on both sides, we get
R = 645.91 km/hr
This is the grouped speed of the aircraft.
To find θ use sine rule.
Do cross multiplication, we get
sin θ = 0.0875
θ = 5.02°
This is known as the drift angle and is the correction the pilot should apply to remain on course.
The heading is the direction the aircraft's nose is pointing which is
The track is the actual direction over the ground which is θ = 5.02°
An alternative method to this would be to separate each vector into vertical and horizontal components and add.
The resultant can be found using Pythagoras.
If you know two points on a line you can solve for slope, m (some people say rise over run, or change in y over change in x). In the attached picture, it's the top equation in blue.
Then you can plug that into the point-slope formula (middle equation, in red), which if needed can be algebraically changed to look like the slope-intercept formula (third equation, in yellow).
But to answer your question, use the point-slope formula.
Then you can plug that into the point-slope formula (middle equation, in red), which if needed can be algebraically changed to look like the slope-intercept formula (third equation, in yellow).
But to answer your question, use the point-slope formula.