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olga_2 [115]
3 years ago
10

The table represents a linear function

Mathematics
1 answer:
Anton [14]3 years ago
8 0

Answer:

the answer is: False

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Find the zeros of the function.
Reika [66]

Answer:

x = - 4, x = - \frac{1}{5}

Step-by-step explanation:

To find the zeros let g(x) = 0, that is

(- 5x - 1)(2x + 8) = 0 ← in standard form

Equate each factor to zero and solve for x

- 5x - 1 = 0 ( add 1 to both sides )

- 5x = 1 ( divide both sides by - 5 )

x = \frac{1}{-5} = - \frac{1}{5}

2x + 8 = 0 ( subtract 8 from both sides )

2x = - 8 ( divide both sides by 2 )

x = - 4

Thus

smaller x = - 4

larger x = - \frac{1}{5}

8 0
3 years ago
How do you determine if a relation is quadratic by calculation differences, analyzing a graph, examining the degree in an equati
Kryger [21]

1) We can determine by the table of values whether a function is a quadratic one by considering this example:

x | y 1st difference 2nd difference

0 0 3 -0 = 3 7-3 = 4

1 3 10 -3 = 7 11 -7 = 4

2 10 21 -10 =11 15 -11 = 4

3 21 36-21 = 15 19-5 = 4

4 36 55-36= 19

5 55

2) Let's subtract the values of y this way:

3 -0 = 3

10 -3 = 7

21 -10 = 11

36 -21 = 15

55 -36 = 19

Now let's subtract the differences we've just found:

7 -3 = 4

11-7 = 4

15-11 = 4

19-15 = 4

So, if the "second difference" is constant (same result) then it means we have a quadratic function just by analyzing the table.

3) Hence, we can determine if this is a quadratic relation calculating the second difference of the y-values if the second difference yields the same value. The graph must be a parabola and the highest coefficient must be 2

4 0
1 year ago
What is Manuel's age?
labwork [276]

Answer: Age:25

Step-by-step explanation:

7 0
3 years ago
3x + 6y= 6<br> 9x - 12y = 18 elimination with multiplication
rjkz [21]

Answer: x = 4y/3+2

   y = 0

Step-by-step explanation:

3 0
3 years ago
match the following trig ratios with the correct equation for the triangle shown below (picture attached)
Sergeu [11.5K]

Answer:

a

Step-by-step explanation:

5 0
3 years ago
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