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Nostrana [21]
2 years ago
9

Find sin(b) in the triangle. A.4/3 B.3/5 C.3/4 D.4/5

Mathematics
1 answer:
DerKrebs [107]2 years ago
7 0

The value of \sin \beta in the given triangle ABC is \dfrac{4}{5}. Option D is correct.

<h3>What are the trigonometric ratios?</h3>

Trigonometric ratios are the ratio of sides of a right angled triangle. There are 6 types of trigonometric ratios: sin, cos, tan, cosec, sec, and cot.

Sine trigonometric ratio is the ratio of perpendicular (side opposite to the angle) to the hypotenuse.

In the given figure, the side opposite to the angle \beta is AC = 4 and the hypotenuse is AB = 5.

So, the sine ratio will be equal to,

\sin \beta=\dfrac{4}{5}

Therefore, the value of \sin \beta in the given triangle ABC is \dfrac{4}{5}. Option D is correct.

Learn more about trigonometric ratios here:

brainly.com/question/1201366

#SPJ1

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