<u>Options</u>
![(A)\left(-\infty , \dfrac23\right]\\\\(B)\left(-\infty , \dfrac23\right) \\\\(C)(\frac23\right, \infty ) \\\\(D) [\frac23\right, \infty )](https://tex.z-dn.net/?f=%28A%29%5Cleft%28-%5Cinfty%20%2C%20%5Cdfrac23%5Cright%5D%5C%5C%5C%5C%28B%29%5Cleft%28-%5Cinfty%20%2C%20%5Cdfrac23%5Cright%29%20%5C%5C%5C%5C%28C%29%28%5Cfrac23%5Cright%2C%20%5Cinfty%20%29%20%5C%5C%5C%5C%28D%29%20%5B%5Cfrac23%5Cright%2C%20%5Cinfty%20%29)
Answer:
Step-by-step explanation:
Given the solution to an inequality
{x|x>2/3}
The solution set does not include 
, therefore, it must be open at the left. Recall that we use a curvy bracket ( to denote openness at the left.
Since x is greater than , the solution set contains all values of larger than up till infinity. Since infinity is an arbitrarily large value, we also use an open bracket at the right.
Therefore, another way to represent the solution {x|x>2/3} is:
The correct option is C.
Answer:
Answer 30^{2}
Step-by-step explanation:
24^{2} + 18^ {2} = c^{2}
576 + 324 = c^{2}
\sqrt{900} c^{2} = 30
hope this helps!
Answer:
Step-by-step explanation:
you can solve for the fractions first, but you have to give them a common denominator
which is in simplest form
then solve for the whole numbers
3-2=1
therefore, the answer is
Answer:
y=9b to the second power t over m
Step-by-step explanation:
should look like this
y=9b^2t/m
