Answer:
Step-by-step explanation:
Assuming there is a punitive removal of one point for an incorrect response.
Five undiscernable choices: 20% chance of guessing correctly -- Expectation: 0.20*(1) + 0.80*(-1) = -0.60
Four undiscernable choices: 25% chance of guessing correctly -- Expectation: 0.25*(1) + 0.75*(-1) = -0.50
I'll use 0.33 as an approzimation for 1/3
Three undiscernable choices: 33% chance of guessing correctly -- Expectation: 0.33*(1) + 0.67*(-1) = -0.33 <== The approximation is a little ugly.
Two undiscernable choices: 50% chance of guessing correctly -- Expectation: 0.50*(1) + 0.50*(-1) = 0.00
And thus we see that only if you can remove three is guessing neutral. There is no time when guessing is advantageous.
One Correct Answer: 100% chance of guessing correctly -- Expectation: 1.00*(1) + 0.00*(-1) = 1.00
Answer:

Step-by-step explanation:
Given

Required
Gaps: -2( )-2( )=8
<em>Fill in in the gaps</em>
The are numerous solutions to this.
One of them is:
Assume y = 0.
So, we have:



Divide through by -2


Fill in the gaps with these values of x and y respectively:
Hence; one solution is: 
Answer:
276 Guests
Step-by-step explanation:
Calculation to determine how many guest were at the wedding
Guests that choose beef =1/3
Guests that choose chicken= 5/12
Guests that choose vegetarian=69
Now let calculate the how many guest were at the wedding
Let x represent the numbers of guest that were present at the wedding
Hence,
x/3 + 5x/12 + 69 = x
9x/12 + 69 = x
12x/12 - 9x/12 = 69
3x/12 = 69
x/4 = 69
x=69*4
x = 276 guests
Therefore the numbers of guests that were at the wedding is 276