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Citrus2011 [14]
3 years ago
11

Afla cate procente reprezinta numarul a din numarul b daca a si b sunt invers proportionale cu numerele 12 si 15

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0

Răspuns:

125%

Explicație pas cu pas:

a și B sunt invers proporționale cu numerele 12 și 15

Proporționalitate inversă:

a = k / y

Prin urmare ;

a = k / 12 - - - (1)

b = k / 15 - - - (2)

Procent care reprezintă a de la b

a = 100%

b = x

k / 12 = 1

k / 15 = x

Înmulțirea încrucișată:

x * k / 12 = k / 15

x = k / 12 ÷ k / 15

x = k / 12 * 15 / k

x = 15/12

x = 1,25

1,25 * 100% = 125%

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Answer:

Q1) The student has a 0.01% probability of passing the test.

Q2) She has a 99.91% probability of passing in the test.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either he gets it correct, or he gets it wrong. So we solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

For this problem, we have that:

Question 1.

There are 50 questions, so n = 50.

The student is going to guess each question, so he has a \pi = \frac{1}{4} = 0.25 probability of getting it right.

He needs to get at least 25 question right.

So we need to find P(X \geq 25).

Using a binomial probability calculator, with n = 50 and \pi = 0.25 we get that P(X \geq 25) = 0.0001.

This means that the student has a 0.01% probability of passing the test.

Question 2.

Now, we need to find P(X \geq 25) with \pi = 0.70. So P(X \geq 25) = 0.9991

She has a 99.91% probability of passing in the test.

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