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Archy [21]
2 years ago
14

Write a question that the database will understand. Which records do not contain "sold"?

Computers and Technology
1 answer:
astraxan [27]2 years ago
4 0

Answer:

b

Explanation:

b

You might be interested in
Write the logical Expression and Draw the Truth table for the <br> following questions
Alja [10]

The logical expressions are

  • (X NOR Y ) OR Z ⇒ (\bar X  \bar + \bar Y) + Z
  • (A NAND B) AND NOT C ⇒ (\bar A \bar \cdot\bar B) \cdot \bar C

<h3>How to determine the logical expressions?</h3>

<u>Logical expression 1</u>

X and Y are linked by the NOR gate.

So, we have:

X NOR Y

The X NOR Y is linked to Z by the OR gate.

So, we have:

(X NOR Y) OR Z

Hence, the logical expression is (X NOR Y ) OR Z ⇒ (\bar X  \bar + \bar Y) + Z

<u>Logical expression 2</u>

A and B are linked by the NAND gate.

So, we have:

A NAND B

The A NAND B is linked to C by the AND gate.

So, we have:

(A NAND B) AND C

Hence, the logical expression is (A NAND B) AND NOT C ⇒ (\bar A \bar \cdot\bar B) \cdot \bar C

See attachment for the truth tables

Read more about truth tables at:

brainly.com/question/27989881

#SPJ1

6 0
1 year ago
Write a program that grades arithmetic quizzes as follows: Ask the user how many questions are in the quiz. Ask the user to ente
kirill115 [55]

Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

int main(){

   int questions, answer;

   cout<<"Questions: ";

   cin>>questions;

   int answerkey[questions];

   cout<<"Enter answer keys: ";

   for(int i = 0; i< questions; i++){

       cin>>answerkey[i];    }

   int correct = 0;

   cout<<"Enter answers: ";

   for(int i = 0; i< questions; i++){

       cin>>answer;

       if(answer == answerkey[i]){

           correct++;        }    }

   cout<<"Correct answers: "<<correct<<endl;

   cout<<"Percentage correct : "<<(100 * correct)/questions<<"%";

   return 0;

}

Explanation:

This declares the number of questions and the answers submitted to each equation

   int questions, answer;

Prompt to get the number of questions

   cout<<"Questions: ";

This gets input for the number of questions

   cin>>questions;

This declares the answerkey as an array

   int answerkey[questions];

Prompt to get the answer key

   cout<<"Enter answer keys: ";

This iteration gets the answer key for each question

<em>    for(int i = 0; i< questions; i++){</em>

<em>        cin>>answerkey[i];    }</em>

This initializes the number of correct answers to 0

   int correct = 0;

Prompt to get the enter the answers

   cout<<"Enter answers: ";

This iterates through the answer keys

   for(int i = 0; i< questions; i++){

This gets the answer to each question

       cin>>answer;

This compares the answer to the answer key of the question

       if(answer == answerkey[i]){

If they are the same, correct is incremented by 1

           correct++;        }    }

Print the number of correct answers

   cout<<"Correct answers: "<<correct<<endl;

Print the percentage of correct answers

   cout<<"Percentage correct : "<<(100 * correct)/questions<<"%";

7 0
3 years ago
Different network scenarios require the
Vladimir [108]

Answer:

a) Viruses

Explanation:

Vulnerability assessment is performed by variety of tools and these can be protocol analyzer, vulnerability scanner, Honeypots, port scanners, honey nets and banner grabbing tools.

Port scanners : they are used to scan the ports which can be exploited by attackers. Most of TCP/IP applications communicate using different ports and attackers can exploit these ports if they are found vulnerable. for example : ports like 80 and 443 are commonly used for HTTP and SSL communication. 22 is used for SSH and if they are open to world then it will allow attackers to use those to get the entry into the system.

Protocol Analyzers : They are used to analyze the packet captures. tools like wireshark, tshark, these tools will help user to decode HTTP/SSL/HTTPS/FTP/RSTP or any application protocols communication. this will help user to understand any unwanted or non-anticipated traffic.

Vulnerability Scanners : They are used to detect the vulnerabilities in the network or systems. these will help administrators to get the alerts whenever there are unanticipated activity. It will have two types of scanners one is active scanner and other is passive scanner. Active scanners will keep on sending probes at the fixed time slots and passibe scanners will be in listening mode all the time. These scanners will alert when a new nodes comes up or goes down or if any system gets compromised.

Honeypots and Honey nets : They are devices or softwares which are having limited security. These devices are made vulnerable purposefully so that attackers can try and attack.  This will help softwares to detect the attackers when they try to exploit these open vulnerabilities. They are deceptions created with purpose.

Banner grabbing Tools : These are tools which will capture the banner information like HTTP protocol version, underlying operating system, open ssl versions being used, server software and similar information. these are important as it will open up potential vulnerabilities in the underlying software. for ex : SSLv3 has a vulnerability known to world and can be exploited by anyone.

4 0
2 years ago
Q: Why can't I log in to Brainly
algol13

Answer:

yes you are probably on a school Chromebook

Explanation:

5 0
3 years ago
In c++
Elodia [21]

Answer:

class studentType: public personType

{

public:

virtual void print() = 0;

virtual void calculateGPA() = 0;

void setID(long id) {

studentId = id;

}

void setCourses(const string c[], int noOfC) {

noOfCourses = noOfC;

for (int i=0; i<noOfCourses; i++) {

courses[i] = c[i];

}

}

void setGrades(const char cG[], int noOfC) {

noOfCourses = noOfC;

for (int i=0; i<noOfCourses; i++) {

coursesGrade[i] = cG[i];

}

}

long getID() {

return studentId;

}

string* getCourses() {

return courses;

}

char* getGrades() {

return coursesGrade;

}

studentType(string fName = "", string lastName = "",

long id = 0, string c[] = NULL, char cG[] = NULL, int noOfC = 0);

private:

long studentId;

string courses[6];

char coursesGrade[6];

int noOfCourses;

};

Explanation:

Code rewritten

5 0
3 years ago
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