Et's give this a go:h(x) = cos(x) / f(x)
derivative (recall the quotient rule)h'(x) = [ f(x) * (-sin(x)) - cos(x)*f'(x) ] / [ f(x) ]^2
simplifyh'(x) = [ -sin(x)*f(x) - cox(x)*f '(x) ] / [ f(x) ]^2h'(π/3) = [ -sin(π/3)*f(π/3) - cox(π/3)*f '(π/3) ] / [ f(π/3) ]^2h'(π/3) = −(3–√/2)∗(3)−(1/2)∗(−7)/(3)2
h'(π/3) = (−33–√/2+7/2)/9
And you can further simplify if you want, I'll stop there.
Answer:
New point location is (2,0)
Explanation:
I’ve attached my work
Hope it helps, let me know if you have any questions !
Y = -3x + 6 = 9
-3x = 3
x = -1
solution is (-1, 9)
Answer:90%
Step-by-step explanation:
It’s a cute angle
Answer:
<h2>(3, -2)</h2>
Step-by-step explanation:
Put the coordinates of the points to the inequality and check:
y < -1/2x + 2
for (2, 3) → x = 2, y = 3
3 < -1/2(2) + 2
3 < -1 + 2
3 < 1 FALSE
============================
for (2, 1) → x = 2, y = 1
1 < -1/2(2) + 2
1 < -1 + 2
1 < 1 FALSE
============================
for (3, -2) → x = 3, y = -2
-2 < -1/2(3) + 2
-2 < -1.5 + 2
-2 < 0.5 TRUE
============================
for (-1, 3) → x = -1, y = 3
3 < -1/2(-1) + 2
3 < 1/2 + 2
3 < 2 1/2 FALSE