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stellarik [79]
2 years ago
9

Answers for 1.2.1 how can I describe a graph

Mathematics
1 answer:
IrinaVladis [17]2 years ago
6 0
I don't know if this is quite what you're looking for but I think it is a diagram showing the relation between variable quantities, typically of two variables, each measured along one of a pair of axes at right angles.
Hope this helps!
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Determine the value of sin 52º 47' (sine of 52 degrees, and 47 minutes). In this case, minutes are 1/60 of a degree.
jeka94

Answer:

D

Step-by-step explanation:

change minutes to degrees

60minutes=1degree

47 mutes=?

47/60=0.78333333°

Add to 52°

52° + 0.78333333°

52.78333333°

so sin 52.7833 =0.7963540136

7 0
3 years ago
Solve the proportional<br> equation below:
Natasha_Volkova [10]

Step-by-step explanation:

the answer is C.

I hope it will be help you.....

3 0
2 years ago
The sum of four times a number and 18 is the same as the difference of fourteen and twice a number
Citrus2011 [14]
4x+18=14-2x \\ 4x=-4-2x \\ 6x=-4 \\ x= \frac{2}{3}
4 0
3 years ago
What is <br><img src="https://tex.z-dn.net/?f=8.4%20-%204.2" id="TexFormula1" title="8.4 - 4.2" alt="8.4 - 4.2" align="absmiddle
STALIN [3.7K]

Answer:

4.2

Step-by-step explanation:

\mathrm{Write\:the\:numbers\:one\:under\:the\:other,\:line\:up\:the\:decimal\:points.}

\mathrm{Add\:trailing\:zeroes\:so\:the\:numbers\:have\:the\:same\:length.}

\begin{matrix}\space\space&8&.&4\\ -&4&.&2\end{matrix}

\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:4-2=2

\frac{\begin{matrix}\space\space&8&.&\textbf{4}\\ -&4&.&\textbf{2}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{2}\end{matrix}}

\mathrm{Place\:the\:decimal\:point\:in\:the\:answer\:directly\:below\:the\:decimal\:points\:in\:the\:terms}

\frac{\begin{matrix}\space\space&8&\textbf{.}&4\\ -&4&\textbf{.}&2\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{.}&2\end{matrix}}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:8-4=4

\frac{\begin{matrix}\space\space&\textbf{8}&.&4\\ -&\textbf{4}&.&2\end{matrix}}{\begin{matrix}\space\space&\textbf{4}&.&2\end{matrix}}

=4.2

3 0
2 years ago
Hey:) can you please help me posted picture of question
Kryger [21]
To expand the given expression we proceed as follows:
(6x²-2x-6)(8x²+7x+8)
=6x²(8x²+7x+8)-2x(8x²+7x+8)-6(8x²+7x+8)
=48x⁴+42x³+48x²-16x³-14x²-16x-48x²-42x-48
putting like terms together:
48x⁴+(42x³-16x³)+(48x²-48x²)+(-16x-42x)-48
=48x⁴+26x³+0x²-58x-48
hence the answer is:
48x⁴+26x³-58x-48
6 0
3 years ago
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