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grin007 [14]
2 years ago
12

Which triangle congurence theorem proves that ABD ≈ CBD?AASSASHLCPCTC​

Mathematics
1 answer:
Liula [17]2 years ago
8 0

Answer:

AAS

Step-by-step explanation:

the ansewer

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A boat is heading towards a lighthouse, whose beacon-light is 145 feet above the water. The boat’s crew measures the angle of el
GREYUIT [131]

Answer:

The ship's horizontal distance from the lighthouse is approximately  1,303.03 feet.

Step-by-step explanation:

3 0
2 years ago
M <2=x+94 what does x equal
Shtirlitz [24]
This is as far as I could get X=-94+m<2
6 0
3 years ago
Given the following functions f(x) and g(x), solve (f+g)(3) and select the correct answer bellow f(x)=6x+3. G(x)=x-7
Likurg_2 [28]

Answer:

17

Step-by-step explanation:

I would just solve them individually for 3 and then add them together. f(x)=6(3)+3 = 21 and g(x)= 3-7= -4

(f+g)(3) = 21-4= 17

5 0
4 years ago
Anyone ...Pls solve
expeople1 [14]
Given:
- Bought n items of product A at 1/5 rs each
- bought n items of product B at 1/4 rs each
He mixed the two items and sold each at 2/9 rs each.
He lost 3 rs in the above batch of articles.

Solution:
revenue = 2n* (2/9) rs = 4n/9 rs
cost = n/5+n/4 rs = n(1/5+1/4)
Profit = revenue-cost = 4n/9-n(1/5+1/4) = -3 rs

Solve for n
4n/9-n(1/5+1/4) = -3 
factor out n
n(4/9-1/5-1/4)=-3
n(80-36-45)/180=-3
-n/180=-3
n=3*180=540

Total number of products bought
= n+n = 540+540 = 1080
6 0
3 years ago
Grasshoppers are distributed at random in a large field according to a Poisson process with parameter a 5 2 per square yard. How
HACTEHA [7]

In this question, the Poisson distribution is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Parameter of 5.2 per square yard:

This means that \mu = 5.2r, in which r is the radius.

How large should the radius R of a circular sampling region be taken so that the probability of finding at least one in the region equals 0.99?

We want:

P(X \geq 1) = 1 - P(X = 0) = 0.99

Thus:

P(X = 0) = 1 - 0.99 = 0.01

We have that:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-5.2r}*(5.2r)^{0}}{(0)!} = e^{-5.2r}

Then

e^{-5.2r} = 0.01

\ln{e^{-5.2r}} = \ln{0.01}

-5.2r = \ln{0.01}

r = -\frac{\ln{0.01}}{5.2}

r = 0.89

Thus, the radius should be of at least 0.89.

Another example of a Poisson distribution is found at brainly.com/question/24098004

3 0
3 years ago
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