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dmitriy555 [2]
3 years ago
9

Worth TONS of points!!! This test is super important so do not give me guesses be at least 95% sure of your answer. Answer all p

arts for brainliest
Let f(x)=7x^3-2x-12 and g(x)=-3x^3-8x^2+10x. What is the function rule for (f+g)(x)

Let f(x)=6-5x and g(x)=6x^2+x. What is the function rule for (fg)(x)

Let x^2+18x=44. What values make an equivalent number sentences after completing the square? x^2+18_____=_______

What is the solution to the system of linear equations?
2x+4y=20
3x+2y=26

Solve the system of equations (there is more than one correct solution)
14x+y=-4
y=3x^2-11x-4

Factor. x^2-6x+8 Enter your answer in the box x^2-6x+8= ( , ) ( , )

Let f(x)=x^2-6x- 27 Enter the x-intercepts of the quadratic function in the boxes.

Answer all of these parts for lots of points AND brainliest! :)
Mathematics
2 answers:
yulyashka [42]3 years ago
5 0

Answer:

(f+g)(x)=7x^3-3x^3-8x^2+10x-2x-12=4x^3 - 8x^2 + 8x - 12


2. fg(x)=6-5(6x^2+x)=6-30x^2-5x


3. x^2+18x=44   | +36

   x^2+18x+36=44+36

   (x+6)^2=80


4. 2x+4y=20   |:2

   x+2y=10

   3x+2y=26

-----------------

  3x-x=26-10

  2x=16

  x=16:2

x=8

x+2y=10

8+2y=10

2y=10-8

2y=2

y=2:2

y=1


5. 14x+y= -4

    y= -4 -14x

  y=3x^2-11x-4

  -4 -14x = 3x^2-11x-4      |+4

      -14x=3x^2-11x    |+14x

      0=3x^2+3x

     3x(x+1)=0

x=0 or x=-1 is the solution


6. x^2-6x+8= x^2-2x-4x+8= x(x-2)-4(x-2)=(x-2)(x-4)


7. x^2-6x-27=0

    x 1= (-6+V36+4*27)/2= (-6+V144)/2= (-6+12)/2=6/2=3

   x2= (-6-12)/2= -18/2= -9


the point are ( 3,0) and (-9.0)

  





Step-by-step explanation:


ycow [4]3 years ago
3 0
1. (f+g)(x)=7x^3-3x^3-8x^2+10x-2x-12=4x^3 - 8x^2 + 8x - 12

2. fg(x)=6-5(6x^2+x)=6-30x^2-5x

3. x^2+18x=44   | +36
    x^2+18x+36=44+36
    (x+6)^2=80

4. 2x+4y=20   |:2
    x+2y=10
    3x+2y=26
-----------------
   3x-x=26-10
   2x=16
   x=16:2
x=8

x+2y=10
8+2y=10
2y=10-8
2y=2
y=2:2
y=1

5. 14x+y= -4
     y= -4 -14x
   y=3x^2-11x-4
   -4 -14x = 3x^2-11x-4      |+4
       -14x=3x^2-11x    |+14x
       0=3x^2+3x
      3x(x+1)=0
x=0 or x=-1 is the solution

6. x^2-6x+8= x^2-2x-4x+8= x(x-2)-4(x-2)=(x-2)(x-4)

7. x^2-6x-27=0
     x 1= (-6+V36+4*27)/2= (-6+V144)/2= (-6+12)/2=6/2=3
    x2= (-6-12)/2= -18/2= -9

the point are ( 3,0) and (-9.0)
   



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3 0
3 years ago
What is the length of a diagonal of a cube with a side length of 10 cm? 200 cm 210cm 300 cm 320cm
Scilla [17]

Answer:

The length of the diagonal of the cube = √(3 × 10²) = √300 cm

Step-by-step explanation:

* Lets revise the properties of the cube

- It has six equal faces all of them are squares

- It has 12 vertices

- The diagonal of the cube is the line joining two vertices in opposite

 faces (look to the attached figure)

- To find the length of the diagonal do that:

# Find the diagonal of the base using Pythagoras theorem

∵ The length of the side of the cube is L

∵ The base is a square

∴ The length of the diagonal d = √(L² + L²) = √(2L²)

- Now use the diagonal of the base and a side of a side face to find the

 diagonal of the cube by Pythagoras theorem

∵ d = √(2L²)

∵ The length of the side of the square = L

∴ The length of the diagonal of the cube = √[d² + L²]

∵ d² = [√(2L²)]² = 2L² ⇒ power 2 canceled the square root

∴ The length of the diagonal of the cube = √[2L² + L²] = √(3L²)

* Now lets solve the problem

∵ The length of the side of the square = 10 cm

∴ The length of the diagonal of the cube = √(3 × 10²) = √300 cm

- Note: you can find the length of the diagonal of any cube using

 this rule Diagonal = √(3L²)

7 0
3 years ago
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