Sodium metal and water form aqueous sodium hydroxide and hydrogen gas:
Na(s) + 2H2O(l) → (Na+)(aq) + 2(OH-)(aq) + H2(g)
Looks like your entries didn't translate well on screen, so find the solution with the coefficients and ions which match this one.
Answer:
+6
Explanation:
We are given;
We are required to determine the oxidation number of S in the compound.
We need to know that;
- The total oxidation number of this compound is Zero
- Oxidation number of Ba metal is +2
- Oxidation number of Oxygen atom is -2
- There is 1 atom of Ba, 1 atom of S and 4 atoms of O in the compound.
Therefore; assuming oxidation number of S is x
Then, (1× 2) + (1 × x) + ( 4 ×(-2)) = 0
2 + x - 8 = 0
x = 6 or +6
Thus oxidation number of Sulfur in BaSO₄ is +6.
Answer:
The diluted solution is 0.65 M
Explanation:
Dilution formula to solve the problem is:
M concentrated . V concentrated = M Diluted . V diluted
We can also make a rule of three though.
In 1000 mL of concentrated solution, we have 13.1 moles of HNO₃
So in 25 mL we have (25 . 13.1 ) / 1000 = 0.327 moles of HNO₃
This moles are also in 0.500 L of diluted solution, the new molarity will be:
0.327 mol / 0.5L = 0.65 M
Molarity of diluted solution must be always lower than concentrated solution, otherwise the excersise is wrong.
If we replace in the formula
13.1 M . 25 mL = 500 mL . M diluted
M diluted = 13.1 m . 25 mL / 500 mL = 0.65 M
Answer:
brainliest plss
Explanation:
Most hydrogen atoms have a nucleus with only a single proton. About 1 in 10,000 hydrogen nuclei, however, also has a neutron; this particular isotope is called deuterium. An extremely rare hydrogen isotope, tritium, has 1 proton and 2 neutrons in its nucleus. ... Most hydrogen atoms have only a proton in the nucleus
