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3 years ago

A prospector pans for gold in a stream.

Chemistry

1 answer:

saveliy_v [14]3 years ago

3 0

Answer:

Mixture

Explanation:

When a prospector scoops up part of the stream bed, the pan contains stream sediments.

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HELP ASAP 50-50 CHANCE

docker41 [41]

Answer: The answer is A, A new element or different atom formed from the original two.

Hope this helps! :D

-TanqR

4 0

4 years ago

the atomic mass of chlorine is 35.45 u. Is it possible for any single atom of chlorine to have a mass number of exactly 35.45? E

KonstantinChe [14]

No, this number is the result of the natural mixture of Cl-35 and Cl-37, which produces the observed value.

The mass of Cl on the periodic table is 35.45 atomic mass units. This is an average mass of the isotopes (different Cl atoms in nature). Most Cl atoms in nature have a relative mass of about 35 atomic mass units. Most of the remaining Cl isotopes have a relative mass of 37 atomic mass units.

8 0

3 years ago

The work function of an element is the energy required to remove an electron from the surface of the solid element. The work fun

Anton [14]

Explanation:

The given data is as follows.

Energy needed for 1 mole = 279.7 kJ = $279.7 \times \frac{1000 J}{1 kJ}$

= 279700 J

Therefore, energy required for 1 atom will be calculated as follows.

$\frac{279700}{6.022 \times 10^{22}}$

= $4.645 \times 10^{-19} J$

As relation between energy and wavelength is as follows.

E = $\frac{hc}{\lambda}$

where, h = planck constant = $6.62 \times 10^{-34} Js$

c = speed of light = $3 \times 10^{8} m/s$

$\lambda$ = wavelength

Therefore, putting given values into the above formula as follows.

E = $\frac{hc}{\lambda}$

$4.645 \times 10^{-19} J$ = $\frac{6.62 \times 10^{-34} Js \times 3 \times 10^{8} m/s}{\lambda}$

$\lambda$ = $4.28 \times 10^{-7} m$

or, = $428 \times 10{-9}$ m

= 428 nm

Thus, we can conclude that the maximum wavelength of light that can remove an electron from an atom on the surface of lithium metal is 428 nm.

4 0

3 years ago

If you change the 2 in front of 2O2 to a 3, what will be the change in the results on the right side of the equation? (1 point)

Simora [160]

Answer:

There is an extra O2 molecule left over

Explanation:

3 0

3 years ago

The compound borazine consists of 40.29% boron, 7.51%

ioda

Answer:

$B_3H_6N_3$

Explanation:

Hello there!

In this case, since the mass percentages in a compound which is wanted to know the molecular formula, can be assumed to be the masses, we first need to compute the moles they have in the formula unit:

$n_B=40.29gB*\frac{1molB}{10.811gB} =3.73molB\\\\n_H=7.51gH*\frac{1molH}{1.01gH} =7.44molH\\\\n_N=52.20gN*\frac{1molN}{14.01gN} =3.73molN$

Next, we divide each moles by the fewest ones (3.73 mol) in order to find the subscript in the empirical formula first:

$B:\frac{3.73}{3.73}=1 \\\\H:\frac{7.44}{3.73}=2\\\\N:\frac{3.73}{3.73}=1$

Then, the empirical formula is BH2N whose molar mass is 26.83 g/mol, so the ratio of molecular to empirical is 80.50/26.83=3; therefore, the molecular formula is three times the empirical one:

$B_3H_6N_3$

Best regards!

7 0

3 years ago