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Afina-wow [57]
3 years ago
9

What is the oxidation number of sulfur in BaSO4?

Chemistry
1 answer:
____ [38]3 years ago
7 0

Answer:

+6

Explanation:

We are given;

  • Compound BaSO₄

We are required to determine the oxidation number of S in the compound.

We need to know that;

  • The total oxidation number of this compound is Zero
  • Oxidation number of Ba metal is +2
  • Oxidation number of Oxygen atom is -2
  • There is 1 atom of Ba, 1 atom of S and 4 atoms of O in the compound.

Therefore; assuming oxidation number of S is x

Then, (1× 2) + (1 × x) + ( 4 ×(-2)) = 0

2 + x - 8 = 0

x = 6 or +6

Thus oxidation number of Sulfur in BaSO₄ is +6.

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A chemist has a small amount of compound ( b.p. = 65 oC) that must be fractionally distilled. Yet, the Chemist does not want to
koban [17]

Answer:

The chemist can either:

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Explanation:

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6 0
3 years ago
The pressure is recorded as 738 mmHg.Convert this measurement to atmosphere (atm)
garri49 [273]
As we know that 760 mmHg is equal to 1 atm.

So,
If 760 mmHg is equal to   =   1 atm
Then
738 mmHg will be equal to   =   X atm

Solving for X,
                                X   =   (738 mmHg × 1 atm) ÷ 760 mmHg

                                X   =   0.971 atm

Result:
           738 mmHg
is equal to 0.971 atm.
4 0
3 years ago
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