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Afina-wow [57]
3 years ago
9

What is the oxidation number of sulfur in BaSO4?

Chemistry
1 answer:
____ [38]3 years ago
7 0

Answer:

+6

Explanation:

We are given;

  • Compound BaSO₄

We are required to determine the oxidation number of S in the compound.

We need to know that;

  • The total oxidation number of this compound is Zero
  • Oxidation number of Ba metal is +2
  • Oxidation number of Oxygen atom is -2
  • There is 1 atom of Ba, 1 atom of S and 4 atoms of O in the compound.

Therefore; assuming oxidation number of S is x

Then, (1× 2) + (1 × x) + ( 4 ×(-2)) = 0

2 + x - 8 = 0

x = 6 or +6

Thus oxidation number of Sulfur in BaSO₄ is +6.

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KonstantinChe [14]

Answer:

The answer to your question is below

Explanation:

A.

[H₃O⁺] = 2 x 10⁻¹⁴ M

pH = ?

Formula

                                    pH = - log [H₃O⁺]

Substitution

                                    pH = - log [2 x 10⁻¹⁴]

Result

                                    pH = 13.7          

B.

[H₃O⁺] = ?

pH = 3.12

Formula

                                   pH = - log [H₃O⁺]

Substitution

                                   3.12 = - log [H₃O⁺]

                                   10^{-3.12} = [H_{3} O^{+}]

Result

                                  [H₃O⁺] = 7.59 M

   

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3 years ago
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h) F

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j) F

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Explanation:

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