Answer:
9 servings of meat.
Step-by-step explanation:
The first ratio you are given is 8:36. You are trying to figure out what 2:__ is.
8/36 x 2/X
Multiply 2 x 36 and get 72. Now divide 72 by 8 to get 9.
Answer:
B. 5626.9
Step-by-step explanation:
• volume of cylinder= pi(r)2h
• plug in the values into the equation
• pi(8)2(28)
pi=3.14 so 3.14(8)2(28)
• multiply all the values
• you get 5629. 73
• b is the closest the that answer since it says approximate
Company A: <span>a one time $100 fee and $50 for each tree
</span>c = 100 + 50t
Company B: <span>one time $80 fee and $60 for each tree
</span>c = 80 + 60t
answer is {c=100+50t c=80+60t (last choice)
Answer:
![Pr = 0.7282](https://tex.z-dn.net/?f=Pr%20%3D%200.7282)
Step-by-step explanation:
Given
--- sample size
-- defective
--- selected
Required
The probability that the batch will be accepted
When the first is selected, the probability that it is okay is:
![Pr(1) = \frac{2100-160}{2100} = \frac{1940}{2100}](https://tex.z-dn.net/?f=Pr%281%29%20%3D%20%5Cfrac%7B2100-160%7D%7B2100%7D%20%3D%20%5Cfrac%7B1940%7D%7B2100%7D)
<em>The subtraction is done to get the number of items that are not defective</em>
Now, there are 2099 left
For the second selection, the probability is:
![Pr(2) =\frac{2099-160}{2099} = \frac{1939}{2099}](https://tex.z-dn.net/?f=Pr%282%29%20%3D%5Cfrac%7B2099-160%7D%7B2099%7D%20%3D%20%5Cfrac%7B1939%7D%7B2099%7D)
Now, there are 2098 left
For the third selection, the probability is:
![Pr(3) =\frac{2098-160}{2098} = \frac{1938}{2098}](https://tex.z-dn.net/?f=Pr%283%29%20%3D%5Cfrac%7B2098-160%7D%7B2098%7D%20%3D%20%5Cfrac%7B1938%7D%7B2098%7D)
Now, there are 2097 left
For the fourth selection, the probability is:
![Pr(4) =\frac{2097-160}{2097} = \frac{1937}{2097}](https://tex.z-dn.net/?f=Pr%284%29%20%3D%5Cfrac%7B2097-160%7D%7B2097%7D%20%3D%20%5Cfrac%7B1937%7D%7B2097%7D)
So, the probability that the batch will be selected is:
![Pr = Pr(1) * Pr(2) * Pr(3) * Pr(4)](https://tex.z-dn.net/?f=Pr%20%3D%20Pr%281%29%20%2A%20Pr%282%29%20%2A%20Pr%283%29%20%2A%20Pr%284%29)
![Pr = \frac{1940}{2100} * \frac{1939}{2099} * \frac{1938}{2098} * \frac{1937}{2097}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B1940%7D%7B2100%7D%20%2A%20%5Cfrac%7B1939%7D%7B2099%7D%20%2A%20%5Cfrac%7B1938%7D%7B2098%7D%20%2A%20%5Cfrac%7B1937%7D%7B2097%7D)
![Pr = 0.7282](https://tex.z-dn.net/?f=Pr%20%3D%200.7282)
Look kid, this question has been up for 3 hours think its time to let it go......... hoped i helped. ✔verified✔