Answer:
Step-by-step explanation:
Answer:
472.2 km
Step-by-step explanation:
Answer:
The expected total amount of time the operator will spend on the calls each day is of 210 minutes.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
n-values of normal variable:
Suppose we have n values from a normally distributed variable. The mean of the sum of all the instances is
and the standard deviation is 
Calls to a customer service center last on average 2.8 minutes.
This means that 
75 calls each day.
This means that 
What is the expected total amount of time in minutes the operator will spend on the calls each day
This is M, so:

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.
36.
90 times 2/5 (or 0.4) is equal to 36
Answer
Find out the what is the percent error in the measurement, to the nearest tenth of a percent .
To prove
Formula

Where error = | Approx - Exact |
As given
Karen measures the width of a garden plot and records that it is 44.25 meters. Its actual width is 45.5 meters.
Approx value = 44.25 meters
Actual value = 45.5 meters
error = | 44.25 - 45.5 |
= |-1.25|
= 1.25
Put in the formula


Percentage error = 2.7%
Therefore the percentage error is 2.7% .