We know that
<span>When two chords intersect each other inside a circle, the products of their segments are equal (</span>Intersecting Chord Theorem)<span>
</span>so
in this problem
AE*EB=DE*EF----> EB=DE*EF/AE
AE=4 in
DE=12 in
EF=8 in
EB=?
EB=DE*EF/AE-----> EB=12*8/4----> EB=24 in
the answer is
EB=24 in
Answer:
Aaron still needs to save $9
Step-by-step explanation:
Assuming the equation is 8a + 56 = 128
8a + 56 = 128
8a = 128 - 56 = 72
8a = 72
a = 72/8 = $9
Step-by-step explanation:
The product of 
is negative whereas the product of 
Answer:
(x-6) (2x+1)
Step-by-step explanation:
1) move everything over to the left side, so subtract 11x and 6.
2x^2 -11x - 6 = 0
2)multiply 2(a term) with -6 (c term)
x^2 -11x -12
3) factor and find what multiples to -12 and adds up to -11. in this case its -12 and positive 1
(x-12) (x+1)
4) divide -12 and 1 by the original a term (2)
(x-6) (x+1/2)
5) move the denominator of 2 over to the x.
(x-6) (2x+1)
OHHHH I REMEMBER THOSE ITS SO EASY GO TO www.anglesmatter.com and type in that lesson and it shows how to do the work and gives you the answer
