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marin [14]
2 years ago
8

Please help if you want BRIANLEIST!!!

Mathematics
1 answer:
bazaltina [42]2 years ago
6 0

Answer:

C

Step-by-step explanation:

2x larger since 14x6.5=91 and 7x6.5=45.5

91/45.5=2

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Please help!!!!!!!!!!!!<br> Will mark brainliest
Sauron [17]

Answer:

○ \displaystyle 25

Step-by-step explanation:

\displaystyle 4 = 2\sqrt{25} - 6 \\ 4 = 2[5] - 6 \\ \\ 4 = 10 - 6

I am joyous to assist you at any time.

3 0
2 years ago
Question 11 (5 points)
mariarad [96]

Answer:

.2

Step-by-step explanation:

Add all the possible outcomes which is 32, then seperate the number of times  5 WILL appear which is 9. Divide 9 by 32 which equals 28% and turn that into a decimal. The answer is .2 hope this helps!!

8 0
3 years ago
Please help ASAP! BRAINLIEST to best/right answer (:
JulsSmile [24]
Just finished doing the math and the correct answer should be B: 5.3  Hope this helps:)
7 0
2 years ago
Read 2 more answers
A liter is equal to 100 centimeters . Is a centiliter a greater measure than a milliliter?
amid [387]
No a milliliter is the same amount as a centimeter
8 0
3 years ago
Read 2 more answers
Can someone plz help me with 11,12,13 plz show work
dimaraw [331]

Answer:

  11.  x = -3+√37 ≈ 3.08276

  12.  x = 11.2

  13.  x = -6 +6√5 ≈ 7.41641

Step-by-step explanation:

In each case, the relation of interest is ...

  (distance to circle near) × (distance to circle far) = (distance to circle near) × (distance to circle far)

When there is only one point of intersection of the secant with the circle—because it is a tangent—then the product is the square of the length of the tangent.

11. 2(2+12) = x(x +6)

  x² +6x -28 = 0

  (x +3)² -37 = 0

  x = -3+√37 ≈ 3.08276

12. 5(5+x) = 9(9)

  5x +25 = 81

  x = 56/5 = 11.2

13. x(x +12) = 12(12)

  x² +12x -144 = 0

  (x +6)² -180 = 0

  x = -6 +√180 ≈ 7.41641

_____

<em>Comment on this secant rule</em>

This rule turns out to apply whether the point of intersection of the secant lines is outside the circle (as in these problems) or inside the circle (as in problem 9). The product of the two distances from the point of intersection to the circle is a constant for a given pair of intersecting secants/chords.

6 0
3 years ago
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