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puteri [66]
2 years ago
8

- Higher Order Thinking The quadratic function

Mathematics
1 answer:
erik [133]2 years ago
8 0

Graphs are used to represent real life models

To calculate the diameter, we substitute the value of x in the function,

From the complete question (see attachment for graph), we have the following observations

  • y represents the diameter of the cereal bowl
  • x represents is depth

The above statement means that:

y is a function of x

So, when the depth is known (<em>i.e. the value of x is known</em>)

We simply substitute this in the function, to calculate the diameter

Take for instance:

\mathbf{x = 8}

The diameter of the bowl would be:

\mathbf{y = 0.32x^2 - 1.6x + 2}

Substitute 8 for x

\mathbf{y = 0.32\times 8^2 - 1.6 \times 8 + 2}

\mathbf{y = 20.48 - 12.8 + 2}

\mathbf{y = 9.68}

The above equation means that:

The diameter of the bowl is <em>9.68</em>, when the depth of the bowl is <em>8</em>

Read more about quadratic functions at:

brainly.com/question/5975436

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Answer:0.27

Step-by-step explanation:

First, we convert the fraction to a decimal number by dividing the numerator by the denominator:

4 / 15 = 0.266

There are two parts to the decimal number above:

Integer Part: 0

Fractional Part: 266

Now, we will make the Fractional Part just two digits (nearest hundredth) by using our rounding rules.*

In this case, Rule II applies, so 4/15 (or 0.266) rounded to the nearest hundredth in decimal format is:

0.27

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Roman55 [17]
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3 years ago
A(3,4),B(5,8),C(7,8) are the vertices of ABC, prove that the line passing through the mid point of AB and AC is parallel to BC
Ede4ka [16]
<h2>Explanation:</h2><h2></h2>

The \ midpoint \ formula \ of \ the \ line \ segment \\ that \ joins \ the \ two \ points \ (x_{1},y_{1}) \ and \ (x_{2},y_{2}) \ is \\ given \ by \ the \ following \ Midpoint \ Formula:\\ \\ Midpoint=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

<h2></h2>
  • Let's name the mid point of AB as c
  • Let's name the mid point of AC as p

Then:

c=(\frac{3+5}{2},\frac{4+8}{2}) \\ \\ c=(\frac{8}{2},\frac{12}{2}) \\ \\ c=(4,6) \\ \\ \\ p=(\frac{3+7}{2},\frac{4+8}{2}) \\ \\ p=(\frac{10}{2},\frac{12}{2}) \\ \\ p=(5,6)

So the slope of the line that passes through c \ and \ p is:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ m_{cp}=\frac{6-6}{5-4}=0

And the slope for BC is:

m_{BC}=\frac{8-8}{7-5}=0

As you can see, both slopes are zero, so these are horizontal lines.

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4 years ago
What are the amplitude, period, phase shift, and midline of f(x) = 7 cos(2x + π) − 3?
8_murik_8 [283]
Thank you for posting your question here at brainly. Feel free to ask more questions.  

The best and most correct answer in this question is 
Amplitude: 7; period: π; phase shift: x = -π / 2; midline: y = −3.<span>       
    </span><span>
Hope my answer would be a great help for you.</span>
4 0
4 years ago
Samantha is measuring the snowfall in a snow Gog for her science project. The first week she measured 3 3/4 inches of snow the s
KATRIN_1 [288]

Samantha measured 13\frac{1}{8} inches for the entire month

Step-by-step explanation:

Samantha is measuring the snowfall in a snow Gog for her science project

  • The first week she measured 3 3/4 inches of snow
  • The second week she measured twice as much snow, and the third week she measured half as much snow as the first week
  • It did not snow at all in the fourth week

We need to find how much snowfall Samantha measured for the entire month

∵ She measured 3\frac{3}{4} inches of snow in the 1st week

- Change the mixed number to improper fraction

∵ 3\frac{3}{4}=\frac{(3)(4)+3}{4}=\frac{12+3}{4}=\frac{15}{4}

∴ She measured \frac{15}{4} inches of snow in the 1st week

∵ She measured twice as much snow as the 1st week in the 2nd week

- Multiply the value of the 1st week by 2

∵ \frac{15}{4} × 2 =  \frac{30}{4}

∴ She measured \frac{30}{4} inches of snow in the 2nd week

∵ She measured half as much snow as the 1st week in the 3rd week

- Multiply the value of the 1st week by 1/2

∵ \frac{15}{4} × \frac{1}{2} =  \frac{15}{8}

∴ She measured \frac{15}{8} inches of snow in the 3rd week

∵ It did not snow at all in the fourth week

- Add the values of the three weeks above to find the amount

  of snowfall she measured for the entire month

∵ The amount of snowfall = \frac{15}{4}+\frac{30}{4}+\frac{15}{8}

- To add the fraction you must make all the denominator same number

  so multiply the 1st and 2nd fractions by 2 up and down to make all

  the denominator equal 8

∴ The amount of snowfall = \frac{30}{8}+\frac{60}{8}+\frac{15}{8}

- Add the numerators and put the sum over 8

∴ The amount of snowfall = \frac{105}{8}

- You can change the improper fraction to mixed number by divide

  105 by 8 and put the reminder over 8

∵ 105 ÷ 8 = 13 and 1/8

∴ The amount of the snowfall = 13\frac{1}{8} inches

Samantha measured 13\frac{1}{8} inches for the entire month

Learn more:

You can learn more about the fraction in brainly.com/question/1312102

#LearnwithBrinaly

6 0
3 years ago
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